यदि (f(x)=\frac{1}{x}) और (g(x)=x-2) हों, तो ((fg)(x)) को सरल करें।

If (f(x)=\frac{1}{x}) and (g(x)=x-2), simplify ((fg)(x)).

Explanation opens after your attempt
Correct Answer

A. (x), \(x\ne 0\)

Step 1

Concept

((fg)(x)=\frac{1}{x}\cdot x-2=x), but the original domain keeps \(x\ne 0\). Restrictions do not disappear after simplification.

Step 2

Why this answer is correct

The correct answer is A. (x), \(x\ne 0\). ((fg)(x)=\frac{1}{x}\cdot x-2=x), but the original domain keeps \(x\ne 0\). Restrictions do not disappear after simplification.

Step 3

Exam Tip

((fg)(x)=\frac{1}{x}\cdot x-2=x), पर मूल डोमेन में \(x\ne 0\) रहेगा। सरल करने से हटे प्रतिबंध वापस नहीं आते।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\frac{1}{x}) और (g(x)=x-2) हों, तो ((fg)(x)) को सरल करें। / If (f(x)=\frac{1}{x}) and (g(x)=x-2), simplify ((fg)(x)).

Correct Answer: A. (x), \(x\ne 0\). Explanation: ((fg)(x)=\frac{1}{x}\cdot x-2=x), पर मूल डोमेन में \(x\ne 0\) रहेगा। सरल करने से हटे प्रतिबंध वापस नहीं आते। / ((fg)(x)=\frac{1}{x}\cdot x-2=x), but the original domain keeps \(x\ne 0\). Restrictions do not disappear after simplification.

Which concept should I revise for this Mathematics MCQ?

((fg)(x)=\frac{1}{x}\cdot x-2=x), but the original domain keeps \(x\ne 0\). Restrictions do not disappear after simplification.

What exam hint can help solve this Mathematics question?

((fg)(x)=\frac{1}{x}\cdot x-2=x), पर मूल डोमेन में \(x\ne 0\) रहेगा। सरल करने से हटे प्रतिबंध वापस नहीं आते।