यदि (f(x)=\frac{1}{x}) और (g(x)=\sqrt{x-2}) हैं, तो ((fg)(x)) का प्रांत क्या होगा?
If (f(x)=\frac{1}{x}) and (g(x)=\sqrt{x-2}), what is the domain of ((fg)(x))?
Explanation opens after your attempt
Correct Answer
A. \(x \geq 2\)
Concept
\(\sqrt{x-2}\) requires \(x \geq 2\) and \(\frac{1}{x}\) requires \(x \neq 0\); the intersection is \(x \geq 2\). Identify the strongest restriction.
Why this answer is correct
The correct answer is A. \(x \geq 2\). \(\sqrt{x-2}\) requires \(x \geq 2\) and \(\frac{1}{x}\) requires \(x \neq 0\); the intersection is \(x \geq 2\). Identify the strongest restriction.
Exam Tip
\(\sqrt{x-2}\) के लिए \(x \geq 2\) और \(\frac{1}{x}\) के लिए \(x \neq 0\); प्रतिच्छेद \(x \geq 2\) है। सबसे कड़ा प्रतिबंध पहचानें।
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