यदि (f(x)=\frac{1}{x-3}) और (g(x)=\frac{1}{x+1}) हैं, तो ((f+g)(x)) का सही सरल रूप क्या है?
If (f(x)=\frac{1}{x-3}) and (g(x)=\frac{1}{x+1}), what is the correct simplified form of ((f+g)(x))?
Explanation opens after your attempt
A. (\frac{2x-2}{(x-3)(x+1)})
Concept
Using a common denominator gives numerator ((x+1)+(x-3)=2x-2). While simplifying, remember original restrictions \(x\ne3,-1\).
Why this answer is correct
The correct answer is A. (\frac{2x-2}{(x-3)(x+1)}). Using a common denominator gives numerator ((x+1)+(x-3)=2x-2). While simplifying, remember original restrictions \(x\ne3,-1\).
Exam Tip
हर समान करने पर अंश ((x+1)+(x-3)=2x-2) मिलता है। सरल करते समय मूल प्रतिबंध \(x\ne3,-1\) भी याद रखें।
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