यदि (f(x)=\frac{1}{x-2}) और (g(x)=\frac{1}{x+4}) हैं, तो ((f+g)(x)) का प्रांत क्या होगा?
If (f(x)=\frac{1}{x-2}) and (g(x)=\frac{1}{x+4}), what is the domain of ((f+g)(x))?
Explanation opens after your attempt
Correct Answer
A. \(x \in \mathbb{R}, x \neq 2, x \neq -4\)
Concept
The denominators (x-2) and (x+4) must not be zero, so \(x \neq 2\) and \(x \neq -4\). In rational functions, check denominators first.
Why this answer is correct
The correct answer is A. \(x \in \mathbb{R}, x \neq 2, x \neq -4\). The denominators (x-2) and (x+4) must not be zero, so \(x \neq 2\) and \(x \neq -4\). In rational functions, check denominators first.
Exam Tip
हरों (x-2) और (x+4) को शून्य नहीं होना चाहिए, इसलिए \(x \neq 2\) और \(x \neq -4\)। परिमेय फलनों में हर पहले जाँचें।
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