यदि (f(x)=\frac{1}{x-1}) और (g(x)=x+3) हैं, तो (\left\(\frac{g}{f}\right\)(x)) का प्रांत क्या है?

If (f(x)=\frac{1}{x-1}) and (g(x)=x+3), what is the domain of (\left\(\frac{g}{f}\right\)(x))?

Explanation opens after your attempt
Correct Answer

A. \(x \in \mathbb{R}, x \neq 1\)

Step 1

Concept

(f(x)) needs \(x \neq 1\), and (f(x)=\frac{1}{x-1}) is never zero. So the only restriction is \(x \neq 1\).

Step 2

Why this answer is correct

The correct answer is A. \(x \in \mathbb{R}, x \neq 1\). (f(x)) needs \(x \neq 1\), and (f(x)=\frac{1}{x-1}) is never zero. So the only restriction is \(x \neq 1\).

Step 3

Exam Tip

(f(x)) के लिए \(x \neq 1\) चाहिए और (f(x)=\frac{1}{x-1}) कभी शून्य नहीं होता। इसलिए केवल \(x \neq 1\) प्रतिबंध है।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\frac{1}{x-1}) और (g(x)=x+3) हैं, तो (\left\(\frac{g}{f}\right\)(x)) का प्रांत क्या है? / If (f(x)=\frac{1}{x-1}) and (g(x)=x+3), what is the domain of (\left\(\frac{g}{f}\right\)(x))?

Correct Answer: A. \(x \in \mathbb{R}, x \neq 1\). Explanation: (f(x)) के लिए \(x \neq 1\) चाहिए और (f(x)=\frac{1}{x-1}) कभी शून्य नहीं होता। इसलिए केवल \(x \neq 1\) प्रतिबंध है। / (f(x)) needs \(x \neq 1\), and (f(x)=\frac{1}{x-1}) is never zero. So the only restriction is \(x \neq 1\).

Which concept should I revise for this Mathematics MCQ?

(f(x)) needs \(x \neq 1\), and (f(x)=\frac{1}{x-1}) is never zero. So the only restriction is \(x \neq 1\).

What exam hint can help solve this Mathematics question?

(f(x)) के लिए \(x \neq 1\) चाहिए और (f(x)=\frac{1}{x-1}) कभी शून्य नहीं होता। इसलिए केवल \(x \neq 1\) प्रतिबंध है।