यदि (f(x)=\frac{1}{x-1}) और (g(x)=x+1) हों, तो ((fg)(x)=1) के हल कौन-से हैं?
If (f(x)=\frac{1}{x-1}) and (g(x)=x+1), what are the solutions of ((fg)(x)=1)?
Explanation opens after your attempt
Correct Answer
A. कोई वास्तविक हल नहींNo real solution
Concept
\(\frac{x+1}{x-1}=1\) gives (x+1=x-1), which is impossible. Also, the condition \(x\ne 1\) remains.
Why this answer is correct
The correct answer is A. कोई वास्तविक हल नहीं / No real solution. \(\frac{x+1}{x-1}=1\) gives (x+1=x-1), which is impossible. Also, the condition \(x\ne 1\) remains.
Exam Tip
\(\frac{x+1}{x-1}=1\) से (x+1=x-1), जो असंभव है। साथ ही \(x\ne 1\) शर्त रहती है।
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