यदि (f(x)=2\sqrt{x}), तो इसका परिसर क्या है?
If (f(x)=2\sqrt{x}), what is its range?
Explanation opens after your attempt
Correct Answer
A. \([0,\infty\))
Concept
\(\sqrt{x}\ge 0\), so \(2\sqrt{x}\ge 0\). At (x=0), the value is (0).
Why this answer is correct
The correct answer is A. \([0,\infty\)). \(\sqrt{x}\ge 0\), so \(2\sqrt{x}\ge 0\). At (x=0), the value is (0).
Exam Tip
\(\sqrt{x}\ge 0\) होता है, इसलिए \(2\sqrt{x}\ge 0\) है। (x=0) पर मान (0) मिलता है।
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