यदि \(f:\mathbb{R}\to\mathbb{R}\) को (f(x)=\begin{cases}x-2,&x\le1\x+2,&x>1\end{cases}) से दिया गया है, तो (f(1)) क्या है?
If \(f:\mathbb{R}\to\mathbb{R}\) is given by (f(x)=\begin{cases}x-2,&x\le1\x+2,&x>1\end{cases}), what is (f(1))?
Explanation opens after your attempt
A. (1)
Concept
The input (x=1) belongs to the first part, so (f(1)=12=1). Use the boundary sign to decide which rule applies.
Why this answer is correct
The correct answer is A. (1). The input (x=1) belongs to the first part, so (f(1)=12=1). Use the boundary sign to decide which rule applies.
Exam Tip
(x=1) पहले भाग में आता है, इसलिए (f(1)=12=1) है। सीमा चिह्न से तय करें कि कौन सा नियम लगेगा।
Login to save your score, XP, coins and progress.
