यदि \(f:\mathbb{R}\to\mathbb{R}\) का परिसर \([5,\infty\)) है और (f(x)=a(x-2)2+b) जहां (a>0), तो नीचे कौन सा युग्म संभव है?
If \(f:\mathbb{R}\to\mathbb{R}\) has range \([5,\infty\)) and (f(x)=a(x-2)2+b), where (a>0), which pair below is possible?
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Correct Answer
A. ((a,b)=(3,5))
Concept
When (a>0), the minimum value is (b). For range \([5,\infty\)), we need (b=5) and (a>0).
Why this answer is correct
The correct answer is A. ((a,b)=(3,5)). When (a>0), the minimum value is (b). For range \([5,\infty\)), we need (b=5) and (a>0).
Exam Tip
(a>0) होने पर न्यूनतम मान (b) होता है। परिसर \([5,\infty\)) के लिए (b=5) और (a>0) चाहिए।
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