यदि \(f:\mathbb{R}\to\mathbb{R}\) का परिसर \([-2,\infty\)) है और (f(x)=(x-a)2+b), तो नीचे कौन सा युग्म संभव है?
If \(f:\mathbb{R}\to\mathbb{R}\) has range \([-2,\infty\)) and (f(x)=(x-a)2+b), which pair below is possible?
Explanation opens after your attempt
Correct Answer
A. ((a,b)=(5,-2))
Concept
The minimum value of ((x-a)2+b) is (b). For range \([-2,\infty\)), we need (b=-2).
Why this answer is correct
The correct answer is A. ((a,b)=(5,-2)). The minimum value of ((x-a)2+b) is (b). For range \([-2,\infty\)), we need (b=-2).
Exam Tip
((x-a)2+b) का न्यूनतम मान (b) होता है। परिसर \([-2,\infty\)) के लिए (b=-2) चाहिए।
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