यदि \(f:\mathbb{R}-{3}\to\mathbb{R}\) को (f(x)=\frac{x-2-9}{x-3}) से दिया गया है, तो (f) का परिसर क्या है?
If \(f:\mathbb{R}-{3}\to\mathbb{R}\) is given by (f(x)=\frac{x-2-9}{x-3}), what is the range of (f)?
Explanation opens after your attempt
Correct Answer
B. \(\mathbb{R}-{6}\)
Concept
On the given domain (f(x)=x+3), but removing (x=3) removes the value (6). The output of an excluded input may also be excluded.
Why this answer is correct
The correct answer is B. \(\mathbb{R}-{6}\). On the given domain (f(x)=x+3), but removing (x=3) removes the value (6). The output of an excluded input may also be excluded.
Exam Tip
दिए गए प्रांत पर (f(x)=x+3) है, पर (x=3) हटने से मान (6) नहीं मिलता। हटाए गए इनपुट का संभावित आउटपुट भी हट सकता है।
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