यदि \(A={x:x\) (15) से छोटे (3) के धनात्मक गुणज हैं(}) और \(B=\{3,6,9,12\}\) हैं तो कौन सा निष्कर्ष सही है?
If \(A={x:x\) is a positive multiple of (3) less than (15)(}) and \(B=\{3,6,9,12\}\), which conclusion is correct?
Explanation opens after your attempt
A. (A=B)
Concept
The positive multiples of (3) less than (15) are (3,6,9,12). The strict boundary excludes (15).
Why this answer is correct
The correct answer is A. (A=B). The positive multiples of (3) less than (15) are (3,6,9,12). The strict boundary excludes (15).
Exam Tip
(15) से छोटे (3) के धनात्मक गुणज (3,6,9,12) हैं। कठोर सीमा में (15) शामिल नहीं है।
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