यदि \(A={x:x\in\mathbb{R},x^2\le 16}\) और \(B={x:x\in\mathbb{R},x>1}\) है, तो \(A\cap B\) क्या है?
If \(A={x:x\in\mathbb{R},x^2\le 16}\) and \(B={x:x\in\mathbb{R},x>1}\), then what is \(A\cap B\)?
Explanation opens after your attempt
Correct Answer
A. ((1,4])
Concept
From \(x^2\le 16\), (A=[-4,4]). With (x>1), the common part is ((1,4]).
Why this answer is correct
The correct answer is A. ((1,4]). From \(x^2\le 16\), (A=[-4,4]). With (x>1), the common part is ((1,4]).
Exam Tip
\(x^2\le 16\) से (A=[-4,4]) है। (x>1) के साथ साझा भाग ((1,4]) है।
Login to save your score, XP, coins and progress.