यदि \(A={x:x\in\mathbb{R},0\le x<5}\) और \(B={x:x\in\mathbb{R},3<x\le 8}\) है, तो (\(A\cup B\)\setminus\(A\cap B\)) क्या है?
If \(A={x:x\in\mathbb{R},0\le x<5}\) and \(B={x:x\in\mathbb{R},3<x\le 8}\), then what is (\(A\cup B\)\setminus\(A\cap B\))?
Explanation opens after your attempt
Correct Answer
A. \([0,3]\cup[5,8]\)
Concept
\(A\cap B=(3,5)\) and \(A\cup B=[0,8]\). Removing the common part leaves \([0,3]\cup[5,8]\).
Why this answer is correct
The correct answer is A. \([0,3]\cup[5,8]\). \(A\cap B=(3,5)\) and \(A\cup B=[0,8]\). Removing the common part leaves \([0,3]\cup[5,8]\).
Exam Tip
\(A\cap B=(3,5)\) और \(A\cup B=[0,8]\) है। साझा भाग हटाने पर \([0,3]\cup[5,8]\) बचता है।
Login to save your score, XP, coins and progress.