यदि \(A={x:x^2=4}\) और \(B={y:y^2-5y+6=0}\) है, तो \(A\times B\) में कितने अवयव होंगे?
If \(A={x:x^2=4}\) and \(B={y:y^2-5y+6=0}\), how many elements are in \(A\times B\)?
Explanation opens after your attempt
Correct Answer
B. (4)
Concept
Here \(A=\{-2,2\}\) and \(B=\{2,3\}\), so (n\(A\times B\)=2\cdot 2=4). In exams, first list each set.
Why this answer is correct
The correct answer is B. (4). Here \(A=\{-2,2\}\) and \(B=\{2,3\}\), so (n\(A\times B\)=2\cdot 2=4). In exams, first list each set.
Exam Tip
यहां \(A=\{-2,2\}\) और \(B=\{2,3\}\), इसलिए (n\(A\times B\)=2\cdot 2=4)। परीक्षा में पहले प्रत्येक समुच्चय के अवयव निकालें।
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