यदि \(A={x\in \mathbb{Z}:x^2\leq x}\) है, तो (n(A)) कितना है?

If \(A={x\in \mathbb{Z}:x^2\leq x}\), what is (n(A))?

Explanation opens after your attempt
Correct Answer

A. (2)

Step 1

Concept

\(x^2\leq x\) is written as (x(x-1)\leq 0).

Step 2

Why this answer is correct

The integer solutions are (0) and (1), so \(A=\{0,1\}\).

Step 3

Exam Tip

For a finite set, count the boundary elements when they are included. चरण 1: \(x^2\leq x\) को (x(x-1)\leq 0) लिखा जाता है। चरण 2: पूर्णांक हल (0) और (1) हैं, इसलिए \(A=\{0,1\}\)। चरण 3: परिमित समुच्चय की गिनती करते समय सीमा सहित अवयव देखें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A={x\in \mathbb{Z}:x^2\leq x}\) है, तो (n(A)) कितना है? / If \(A={x\in \mathbb{Z}:x^2\leq x}\), what is (n(A))?

Correct Answer: A. (2). Explanation: चरण 1: \(x^2\leq x\) को (x(x-1)\leq 0) लिखा जाता है। चरण 2: पूर्णांक हल (0) और (1) हैं, इसलिए \(A=\{0,1\}\)। चरण 3: परिमित समुच्चय की गिनती करते समय सीमा सहित अवयव देखें। / Step 1: \(x^2\leq x\) is written as (x(x-1)\leq 0). Step 2: The integer solutions are (0) and (1), so \(A=\{0,1\}\). Step 3: For a finite set, count the boundary elements when they are included.

Which concept should I revise for this Mathematics MCQ?

\(x^2\leq x\) is written as (x(x-1)\leq 0).

What exam hint can help solve this Mathematics question?

For a finite set, count the boundary elements when they are included. चरण 1: \(x^2\leq x\) को (x(x-1)\leq 0) लिखा जाता है। चरण 2: पूर्णांक हल (0) और (1) हैं, इसलिए \(A=\{0,1\}\)। चरण 3: परिमित समुच्चय की गिनती करते समय सीमा सहित अवयव देखें।