यदि \(A={x\in \mathbb{Z}:x^2\leq x}\) है, तो (n(A)) कितना है?
If \(A={x\in \mathbb{Z}:x^2\leq x}\), what is (n(A))?
Explanation opens after your attempt
A. (2)
Concept
\(x^2\leq x\) is written as (x(x-1)\leq 0).
Why this answer is correct
The integer solutions are (0) and (1), so \(A=\{0,1\}\).
Exam Tip
For a finite set, count the boundary elements when they are included. चरण 1: \(x^2\leq x\) को (x(x-1)\leq 0) लिखा जाता है। चरण 2: पूर्णांक हल (0) और (1) हैं, इसलिए \(A=\{0,1\}\)। चरण 3: परिमित समुच्चय की गिनती करते समय सीमा सहित अवयव देखें।
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