यदि \(A={x\in\mathbb{Z}:-2\le x\le2}\) और \(B={y\in\mathbb{Z}:y^2=4}\), तो \(A\times B\) में (x+y=0) वाले युग्मों की संख्या कितनी है?
If \(A={x\in\mathbb{Z}:-2\le x\le2}\) and \(B={y\in\mathbb{Z}:y^2=4}\), how many pairs in \(A\times B\) satisfy (x+y=0)?
Explanation opens after your attempt
Correct Answer
B. (2)
Concept
\(B=\{-2,2\}\), and the pairs are ((2,-2)) and ((-2,2)). Keep the sets of both coordinates separate while applying the equation.
Why this answer is correct
The correct answer is B. (2). \(B=\{-2,2\}\), and the pairs are ((2,-2)) and ((-2,2)). Keep the sets of both coordinates separate while applying the equation.
Exam Tip
\(B=\{-2,2\}\) है और युग्म ((2,-2)) तथा ((-2,2)) मिलते हैं। समीकरण लगाते समय दोनों निर्देशांक का समुच्चय अलग रखें।
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