यदि \(A={x\in\mathbb{R}:x\ne0}\) और \(B={x\in\mathbb{R}:x^2>0}\), तो \(A\triangle B\) क्या है?

If \(A={x\in\mathbb{R}:x\ne0}\) and \(B={x\in\mathbb{R}:x^2>0}\), what is \(A\triangle B\)?

Explanation opens after your attempt
Correct Answer

A. \(\varnothing\)

Step 1

Concept

For real numbers, \(x^2>0\) exactly when \(x\ne0\). Thus (A=B), and the symmetric difference is \(\varnothing\).

Step 2

Why this answer is correct

The correct answer is A. \(\varnothing\). For real numbers, \(x^2>0\) exactly when \(x\ne0\). Thus (A=B), and the symmetric difference is \(\varnothing\).

Step 3

Exam Tip

वास्तविक संख्याओं में \(x^2>0\) ठीक तब होता है जब \(x\ne0\)। इसलिए (A=B) और सममित अंतर \(\varnothing\) है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(A={x\in\mathbb{R}:x\ne0}\) और \(B={x\in\mathbb{R}:x^2>0}\), तो \(A\triangle B\) क्या है? / If \(A={x\in\mathbb{R}:x\ne0}\) and \(B={x\in\mathbb{R}:x^2>0}\), what is \(A\triangle B\)?

Correct Answer: A. \(\varnothing\). Explanation: वास्तविक संख्याओं में \(x^2>0\) ठीक तब होता है जब \(x\ne0\)। इसलिए (A=B) और सममित अंतर \(\varnothing\) है। / For real numbers, \(x^2>0\) exactly when \(x\ne0\). Thus (A=B), and the symmetric difference is \(\varnothing\).

Which concept should I revise for this Mathematics MCQ?

For real numbers, \(x^2>0\) exactly when \(x\ne0\). Thus (A=B), and the symmetric difference is \(\varnothing\).

What exam hint can help solve this Mathematics question?

वास्तविक संख्याओं में \(x^2>0\) ठीक तब होता है जब \(x\ne0\)। इसलिए (A=B) और सममित अंतर \(\varnothing\) है।