यदि \(A={x \in \mathbb{R}:x^2-4=0}\), तो (A) किसके समान है?

If \(A={x \in \mathbb{R}:x^2-4=0}\), which set is equal to (A)?

Explanation opens after your attempt
Correct Answer

A. ({-2,2})

Step 1

Concept

From \(x^2-4=0\), we get \(x^2=4\).

Step 2

Why this answer is correct

The real solutions are (x=-2) and (x=2).

Step 3

Exam Tip

Hence \(A=\{-2,2\}\). चरण 1: \(x^2-4=0\) से \(x^2=4\) मिलता है। चरण 2: वास्तविक हल (x=-2) और (x=2) हैं। चरण 3: इसलिए \(A=\{-2,2\}\)।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A={x \in \mathbb{R}:x^2-4=0}\), तो (A) किसके समान है? / If \(A={x \in \mathbb{R}:x^2-4=0}\), which set is equal to (A)?

Correct Answer: A. ({-2,2}). Explanation: चरण 1: \(x^2-4=0\) से \(x^2=4\) मिलता है। चरण 2: वास्तविक हल (x=-2) और (x=2) हैं। चरण 3: इसलिए \(A=\{-2,2\}\)। / Step 1: From \(x^2-4=0\), we get \(x^2=4\). Step 2: The real solutions are (x=-2) and (x=2). Step 3: Hence \(A=\{-2,2\}\).

Which concept should I revise for this Mathematics MCQ?

From \(x^2-4=0\), we get \(x^2=4\).

What exam hint can help solve this Mathematics question?

Hence \(A=\{-2,2\}\). चरण 1: \(x^2-4=0\) से \(x^2=4\) मिलता है। चरण 2: वास्तविक हल (x=-2) और (x=2) हैं। चरण 3: इसलिए \(A=\{-2,2\}\)।