यदि \(A={x\in\mathbb{R}: -2<x\le 6}\), \(B={x\in\mathbb{R}: 1\le x<8}\) और \(C={x\in\mathbb{R}: 4<x\le 10}\), तो (\(A\cup C\)-B) क्या है?
If \(A={x\in\mathbb{R}: -2<x\le 6}\), \(B={x\in\mathbb{R}: 1\le x<8}\), and \(C={x\in\mathbb{R}: 4<x\le 10}\), what is (\(A\cup C\)-B)?
Explanation opens after your attempt
Correct Answer
A. \((-2,1)\cup[8,10]\)
Concept
\(A\cup C=(-2,10]), and removing (B=[1,8)\) gives \((-2,1)\cup[8,10]\). Watch open and closed endpoints carefully.
Why this answer is correct
The correct answer is A. \((-2,1)\cup[8,10]\). \(A\cup C=(-2,10]), and removing (B=[1,8)\) gives \((-2,1)\cup[8,10]\). Watch open and closed endpoints carefully.
Exam Tip
\(A\cup C=(-2,10]) है और (B=[1,8)\) हटाने पर \((-2,1)\cup[8,10]\) मिलता है। सिरों के खुले-बंद होने पर ध्यान दें।
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