\(यदि (A={x\in\mathbb{N}: x\le 20,\ x\) is prime\(}) और (B={x\in\mathbb{N}: x<20,\ x\) is odd}), तो (A-B) क्या है?

\(If (A={x\in\mathbb{N}: x\le 20,\ x\) is prime\(}) and (B={x\in\mathbb{N}: x<20,\ x\) is odd}), what is (A-B)?

Explanation opens after your attempt
Correct Answer

A. ({2})

Step 1

Concept

All odd primes in (A) are in (B), so only (2) remains. (19) is also in (B) because it is odd and less than (20).

Step 2

Why this answer is correct

The correct answer is A. ({2}). All odd primes in (A) are in (B), so only (2) remains. (19) is also in (B) because it is odd and less than (20).

Step 3

Exam Tip

(A) के सभी विषम अभाज्य (B) में चले जाते हैं, केवल (2) बचता है। (19) भी (B) में है क्योंकि वह विषम और (20) से छोटा है।

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Mathematics Answer, Explanation and Revision Hints

\(यदि (A={x\in\mathbb{N}: x\le 20,\ x\) is prime\(}) और (B={x\in\mathbb{N}: x<20,\ x\) is odd}), तो (A-B) क्या है? \(/ If (A={x\in\mathbb{N}: x\le 20,\ x\) is prime\(}) and (B={x\in\mathbb{N}: x<20,\ x\) is odd}), what is (A-B)?

Correct Answer: A. ({2}). Explanation: (A) के सभी विषम अभाज्य (B) में चले जाते हैं, केवल (2) बचता है। (19) भी (B) में है क्योंकि वह विषम और (20) से छोटा है। / All odd primes in (A) are in (B), so only (2) remains. (19) is also in (B) because it is odd and less than (20).

Which concept should I revise for this Mathematics MCQ?

All odd primes in (A) are in (B), so only (2) remains. (19) is also in (B) because it is odd and less than (20).

What exam hint can help solve this Mathematics question?

(A) के सभी विषम अभाज्य (B) में चले जाते हैं, केवल (2) बचता है। (19) भी (B) में है क्योंकि वह विषम और (20) से छोटा है।