यदि (A\triangle B=\(A\cap B'\)\cup\(A'\cap B\)), तो (\(A\triangle B\)') किसके बराबर है?
If (A\triangle B=\(A\cap B'\)\cup\(A'\cap B\)), what is (\(A\triangle B\)') equal to?
Explanation opens after your attempt
Correct Answer
A. \(\(A\cap B\)\cup\(A'\cap B'\))
Concept
The symmetric difference contains elements in exactly one set. Its complement contains elements in both or in neither, that is (\(A\cap B\)\cup\(A'\cap B'\)).
Why this answer is correct
The correct answer is A. \(\(A\cap B\)\cup\(A'\cap B'\)). The symmetric difference contains elements in exactly one set. Its complement contains elements in both or in neither, that is (\(A\cap B\)\cup\(A'\cap B'\)).
Exam Tip
सममित अंतर में वे अवयव हैं जो केवल एक समुच्चय में हों। उसका पूरक वे अवयव हैं जो दोनों में हों या दोनों में न हों, यानी (\(A\cap B\)\cup\(A'\cap B'\))।
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