यदि \(A\subseteq B\subseteq C\), (n(C)=95), (n(B)=61) और (n(A)=28) है, तो (n(C-B)) कितना होगा?
If \(A\subseteq B\subseteq C\), (n(C)=95), (n(B)=61), and (n(A)=28), what is (n(C-B))?
Explanation opens after your attempt
A. (34)
Concept
(B) lies completely inside (C), so (n(C-B)=95-61=34). In a nested Venn diagram, subtract the inner part from the larger set.
Why this answer is correct
The correct answer is A. (34). (B) lies completely inside (C), so (n(C-B)=95-61=34). In a nested Venn diagram, subtract the inner part from the larger set.
Exam Tip
(B) पूरा (C) के अंदर है, इसलिए (n(C-B)=95-61=34)। nested वेन आरेख में बड़े से अंदर वाले भाग को घटाएं।
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