यदि (A) और (B) सीमित समुच्चय हैं तथा (n\(A\cup B\)=n(A)+n(B)), तो कौन-सा निष्कर्ष सही है?

If (A) and (B) are finite sets and (n\(A\cup B\)=n(A)+n(B)), which conclusion is correct?

Explanation opens after your attempt
Correct Answer

A. \(A\cap B=\varnothing\)

Step 1

Concept

In the general formula, (n\(A\cap B\)) is subtracted. The equality holds only when (n\(A\cap B\)=0), that is \(A\cap B=\varnothing\).

Step 2

Why this answer is correct

The correct answer is A. \(A\cap B=\varnothing\). In the general formula, (n\(A\cap B\)) is subtracted. The equality holds only when (n\(A\cap B\)=0), that is \(A\cap B=\varnothing\).

Step 3

Exam Tip

सामान्य सूत्र में (n\(A\cap B\)) घटता है। योग बराबर तभी होगा जब (n\(A\cap B\)=0), यानी \(A\cap B=\varnothing\)।

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Mathematics Answer, Explanation and Revision Hints

यदि (A) और (B) सीमित समुच्चय हैं तथा (n\(A\cup B\)=n(A)+n(B)), तो कौन-सा निष्कर्ष सही है? / If (A) and (B) are finite sets and (n\(A\cup B\)=n(A)+n(B)), which conclusion is correct?

Correct Answer: A. \(A\cap B=\varnothing\). Explanation: सामान्य सूत्र में (n\(A\cap B\)) घटता है। योग बराबर तभी होगा जब (n\(A\cap B\)=0), यानी \(A\cap B=\varnothing\)। / In the general formula, (n\(A\cap B\)) is subtracted. The equality holds only when (n\(A\cap B\)=0), that is \(A\cap B=\varnothing\).

Which concept should I revise for this Mathematics MCQ?

In the general formula, (n\(A\cap B\)) is subtracted. The equality holds only when (n\(A\cap B\)=0), that is \(A\cap B=\varnothing\).

What exam hint can help solve this Mathematics question?

सामान्य सूत्र में (n\(A\cap B\)) घटता है। योग बराबर तभी होगा जब (n\(A\cap B\)=0), यानी \(A\cap B=\varnothing\)।