यदि \(A=\{1,2\}\) और \(B=\{2,3\}\), तो \(P(A)\cup P(B)\) में कितने अवयव हैं?

If \(A=\{1,2\}\) and \(B=\{2,3\}\), how many elements are in \(P(A)\cup P(B)\)?

Explanation opens after your attempt
Correct Answer

B. (6)

Step 1

Concept

(P(A)) and (P(B)) have \(\varnothing\) and ({2}) in common, so the total is (4+4-2=6). Remove duplicates in the union of power sets.

Step 2

Why this answer is correct

The correct answer is B. (6). (P(A)) and (P(B)) have \(\varnothing\) and ({2}) in common, so the total is (4+4-2=6). Remove duplicates in the union of power sets.

Step 3

Exam Tip

(P(A)) और (P(B)) में \(\varnothing\) तथा ({2}) समान हैं, इसलिए कुल (4+4-2=6)। पावर सेटों के संघ में दोहराव हटाएं।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{1,2\}\) और \(B=\{2,3\}\), तो \(P(A)\cup P(B)\) में कितने अवयव हैं? / If \(A=\{1,2\}\) and \(B=\{2,3\}\), how many elements are in \(P(A)\cup P(B)\)?

Correct Answer: B. (6). Explanation: (P(A)) और (P(B)) में \(\varnothing\) तथा ({2}) समान हैं, इसलिए कुल (4+4-2=6)। पावर सेटों के संघ में दोहराव हटाएं। / (P(A)) and (P(B)) have \(\varnothing\) and ({2}) in common, so the total is (4+4-2=6). Remove duplicates in the union of power sets.

Which concept should I revise for this Mathematics MCQ?

(P(A)) and (P(B)) have \(\varnothing\) and ({2}) in common, so the total is (4+4-2=6). Remove duplicates in the union of power sets.

What exam hint can help solve this Mathematics question?

(P(A)) और (P(B)) में \(\varnothing\) तथा ({2}) समान हैं, इसलिए कुल (4+4-2=6)। पावर सेटों के संघ में दोहराव हटाएं।