यदि \(A=\{1,2,3\}\), \(B=\{2,3,4\}\) और \(C=\{3,4,5\}\) हैं, तो (A\times\(B\cap C\)) में कितने अवयव होंगे?

If \(A=\{1,2,3\}\), \(B=\{2,3,4\}\) and \(C=\{3,4,5\}\), how many elements are in (A\times\(B\cap C\))?

Explanation opens after your attempt
Correct Answer

A. (6)

Step 1

Concept

\(B\cap C={3,4}\), so (n(A\times\(B\cap C\))=3\times2=6). Find the intersection before counting the Cartesian product.

Step 2

Why this answer is correct

The correct answer is A. (6). \(B\cap C={3,4}\), so (n(A\times\(B\cap C\))=3\times2=6). Find the intersection before counting the Cartesian product.

Step 3

Exam Tip

\(B\cap C={3,4}\), इसलिए (n(A\times\(B\cap C\))=3\times2=6)। प्रतिच्छेद निकालकर ही कार्तीय गुणन गिनें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{1,2,3\}\), \(B=\{2,3,4\}\) और \(C=\{3,4,5\}\) हैं, तो (A\times\(B\cap C\)) में कितने अवयव होंगे? / If \(A=\{1,2,3\}\), \(B=\{2,3,4\}\) and \(C=\{3,4,5\}\), how many elements are in (A\times\(B\cap C\))?

Correct Answer: A. (6). Explanation: \(B\cap C={3,4}\), इसलिए (n(A\times\(B\cap C\))=3\times2=6)। प्रतिच्छेद निकालकर ही कार्तीय गुणन गिनें। / \(B\cap C={3,4}\), so (n(A\times\(B\cap C\))=3\times2=6). Find the intersection before counting the Cartesian product.

Which concept should I revise for this Mathematics MCQ?

\(B\cap C={3,4}\), so (n(A\times\(B\cap C\))=3\times2=6). Find the intersection before counting the Cartesian product.

What exam hint can help solve this Mathematics question?

\(B\cap C={3,4}\), इसलिए (n(A\times\(B\cap C\))=3\times2=6)। प्रतिच्छेद निकालकर ही कार्तीय गुणन गिनें।