यदि \(A=\{1,2,3,4\}\), \(B=\{2,4,6\}\), \(C=\{3,4,5\}\) और \(D=\{4,6,8\}\) है, तो (\(A\times B\)\setminus\(C\times D\)) में कितने अवयव होंगे?
If \(A=\{1,2,3,4\}\), \(B=\{2,4,6\}\), \(C=\{3,4,5\}\) and \(D=\{4,6,8\}\), how many elements are in (\(A\times B\)\setminus\(C\times D\))?
Explanation opens after your attempt
Correct Answer
C. (8)
Concept
(n\(A\times B\)=12), and (\(A\times B\)\cap\(C\times D\)=\(A\cap C\)\times\(B\cap D\)) has (4) elements. So the difference has (12-4=8) elements.
Why this answer is correct
The correct answer is C. (8). (n\(A\times B\)=12), and (\(A\times B\)\cap\(C\times D\)=\(A\cap C\)\times\(B\cap D\)) has (4) elements. So the difference has (12-4=8) elements.
Exam Tip
(n\(A\times B\)=12) और (\(A\times B\)\cap\(C\times D\)=\(A\cap C\)\times\(B\cap D\)) में (4) अवयव हैं। इसलिए अंतर में (12-4=8) अवयव होंगे।
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