यदि \(A=\{1,2,3,4\}\) और \(B=\{3,4,5\}\), तो (\(A\times B\)\setminus\(B\times A\)) में कितने युग्म हैं?

If \(A=\{1,2,3,4\}\) and \(B=\{3,4,5\}\), how many pairs are in (\(A\times B\)\setminus\(B\times A\))?

Explanation opens after your attempt
Correct Answer

C. (8)

Step 1

Concept

(n\(A\times B\)=12), and the common part (\(A\cap B\)\times\(A\cap B\)) has (4) pairs. So the difference has (12-4=8) pairs.

Step 2

Why this answer is correct

The correct answer is C. (8). (n\(A\times B\)=12), and the common part (\(A\cap B\)\times\(A\cap B\)) has (4) pairs. So the difference has (12-4=8) pairs.

Step 3

Exam Tip

(n\(A\times B\)=12) और समान भाग (\(A\cap B\)\times\(A\cap B\)) के (4) युग्म हैं। इसलिए अंतर में (12-4=8) युग्म होंगे।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{1,2,3,4\}\) और \(B=\{3,4,5\}\), तो (\(A\times B\)\setminus\(B\times A\)) में कितने युग्म हैं? / If \(A=\{1,2,3,4\}\) and \(B=\{3,4,5\}\), how many pairs are in (\(A\times B\)\setminus\(B\times A\))?

Correct Answer: C. (8). Explanation: (n\(A\times B\)=12) और समान भाग (\(A\cap B\)\times\(A\cap B\)) के (4) युग्म हैं। इसलिए अंतर में (12-4=8) युग्म होंगे। / (n\(A\times B\)=12), and the common part (\(A\cap B\)\times\(A\cap B\)) has (4) pairs. So the difference has (12-4=8) pairs.

Which concept should I revise for this Mathematics MCQ?

(n\(A\times B\)=12), and the common part (\(A\cap B\)\times\(A\cap B\)) has (4) pairs. So the difference has (12-4=8) pairs.

What exam hint can help solve this Mathematics question?

(n\(A\times B\)=12) और समान भाग (\(A\cap B\)\times\(A\cap B\)) के (4) युग्म हैं। इसलिए अंतर में (12-4=8) युग्म होंगे।