असमानता \(x^2\ge 16\) संख्या रेखा पर किस रूप में दिखेगी?
How will \(x^2\ge 16\) appear on the number line?
Explanation opens after your attempt
C. (\(-\infty,-4]\cup[4,\infty\))
Concept
\(x^2\ge 16\) means \(|x|\ge 4\), giving two closed outer regions. In exams, include (-4) and (4) for \(\ge\).
Why this answer is correct
The correct answer is C. (\(-\infty,-4]\cup[4,\infty\)). \(x^2\ge 16\) means \(|x|\ge 4\), giving two closed outer regions. In exams, include (-4) and (4) for \(\ge\).
Exam Tip
\(x^2\ge 16\) में \(|x|\ge 4\), इसलिए बाहर के दो closed भाग मिलते हैं। परीक्षा में \(\ge\) होने पर (-4) और (4) शामिल करें।
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