शब्द (PERMUTATION) के अक्षरों की अलग-अलग व्यवस्थाएं कितनी होंगी?
How many distinct arrangements are possible using the letters of (PERMUTATION)?
Explanation opens after your attempt
A. (19958400)
Concept
There are (11) letters with (T) repeated twice and all others distinct. Hence \(\frac{11!}{2!}=19958400\).
Why this answer is correct
The correct answer is A. (19958400). There are (11) letters with (T) repeated twice and all others distinct. Hence \(\frac{11!}{2!}=19958400\).
Exam Tip
(11) अक्षरों में (T) दो बार है और बाकी अलग हैं। इसलिए \(\frac{11!}{2!}=19958400\) है।
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