शब्द (MISSISSIPPI) के अक्षरों की अलग-अलग व्यवस्थाएं कितनी होंगी?

How many distinct arrangements are possible using the letters of (MISSISSIPPI)?

Explanation opens after your attempt
Correct Answer

A. (34650)

Step 1

Concept

There are (11) letters with (I) four times, (S) four times and (P) twice. Hence the number is \(\frac{11!}{4!4!2!}=34650\).

Step 2

Why this answer is correct

The correct answer is A. (34650). There are (11) letters with (I) four times, (S) four times and (P) twice. Hence the number is \(\frac{11!}{4!4!2!}=34650\).

Step 3

Exam Tip

(11) अक्षरों में (I) चार, (S) चार और (P) दो बार हैं। इसलिए संख्या \(\frac{11!}{4!4!2!}=34650\) है।

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शब्द (MISSISSIPPI) के अक्षरों की अलग-अलग व्यवस्थाएं कितनी होंगी? / How many distinct arrangements are possible using the letters of (MISSISSIPPI)?

Correct Answer: A. (34650). Explanation: (11) अक्षरों में (I) चार, (S) चार और (P) दो बार हैं। इसलिए संख्या \(\frac{11!}{4!4!2!}=34650\) है। / There are (11) letters with (I) four times, (S) four times and (P) twice. Hence the number is \(\frac{11!}{4!4!2!}=34650\).

Which concept should I revise for this Mathematics MCQ?

There are (11) letters with (I) four times, (S) four times and (P) twice. Hence the number is \(\frac{11!}{4!4!2!}=34650\).

What exam hint can help solve this Mathematics question?

(11) अक्षरों में (I) चार, (S) चार और (P) दो बार हैं। इसलिए संख्या \(\frac{11!}{4!4!2!}=34650\) है।