शब्द (MATHEMATICS) के अक्षरों की अलग-अलग व्यवस्थाएं कितनी होंगी?
How many distinct arrangements are possible using the letters of (MATHEMATICS)?
Explanation opens after your attempt
Correct Answer
A. (9979200)
Concept
There are (11) letters with (M,A,T) each repeated twice, so \(\frac{11!}{2!2!2!}=4989600\). In exams, divide by factorials of all repeated letters.
Why this answer is correct
The correct answer is A. (9979200). There are (11) letters with (M,A,T) each repeated twice, so \(\frac{11!}{2!2!2!}=4989600\). In exams, divide by factorials of all repeated letters.
Exam Tip
(11) अक्षरों में (M,A,T) दो-दो बार आते हैं, इसलिए \(\frac{11!}{2!2!2!}=4989600\)। परीक्षा में सभी repeated letters के factorial से भाग दें।
Login to save your score, XP, coins and progress.