असमानताओं \(x\geq 0\), \(y\geq 0\), \(x+y\leq 6\), \(x+2y\leq 8\) के हल-क्षेत्र में कितने कोने हैं?

How many corner points are in the solution region of \(x\geq 0\), \(y\geq 0\), \(x+y\leq 6\), and \(x+2y\leq 8\)?

Explanation opens after your attempt
Correct Answer

D. (4)

Step 1

Concept

The corners are ((0,0)), ((6,0)), ((4,2)), and ((0,4)). Hence there are (4) corner points.

Step 2

Why this answer is correct

The correct answer is D. (4). The corners are ((0,0)), ((6,0)), ((4,2)), and ((0,4)). Hence there are (4) corner points.

Step 3

Exam Tip

कोने ((0,0)), ((6,0)), ((4,2)), ((0,4)) हैं। इसलिए कुल (4) कोने बनते हैं।

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Mathematics Answer, Explanation and Revision Hints

असमानताओं \(x\geq 0\), \(y\geq 0\), \(x+y\leq 6\), \(x+2y\leq 8\) के हल-क्षेत्र में कितने कोने हैं? / How many corner points are in the solution region of \(x\geq 0\), \(y\geq 0\), \(x+y\leq 6\), and \(x+2y\leq 8\)?

Correct Answer: D. (4). Explanation: कोने ((0,0)), ((6,0)), ((4,2)), ((0,4)) हैं। इसलिए कुल (4) कोने बनते हैं। / The corners are ((0,0)), ((6,0)), ((4,2)), and ((0,4)). Hence there are (4) corner points.

Which concept should I revise for this Mathematics MCQ?

The corners are ((0,0)), ((6,0)), ((4,2)), and ((0,4)). Hence there are (4) corner points.

What exam hint can help solve this Mathematics question?

कोने ((0,0)), ((6,0)), ((4,2)), ((0,4)) हैं। इसलिए कुल (4) कोने बनते हैं।