अंकों (1,2,3,4,5,6,7,8,9) से बिना पुनरावृत्ति (400000) से छोटी कितनी (6)-अंकीय विषम संख्याएं बनेंगी?
How many (6)-digit odd numbers less than (400000) can be formed from digits (1,2,3,4,5,6,7,8,9) without repetition?
Explanation opens after your attempt
Correct Answer
C. (10920)
Concept
The first digit must be (1,2,3), and the last digit must be odd, so cases are needed. Count the bound and oddness together.
Why this answer is correct
The correct answer is C. (10920). The first digit must be (1,2,3), and the last digit must be odd, so cases are needed. Count the bound and oddness together.
Exam Tip
पहला अंक (1,2,3) होना चाहिए और अंतिम अंक विषम होना चाहिए, इसलिए केस बनते हैं। सीमा और विषमता दोनों को साथ गिनें।
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