अंकों (0,1,2,3,4,5,6,7,8) से बिना पुनरावृत्ति (5) अंकों की कितनी विषम संख्याएं बनेंगी?
How many (5)-digit odd numbers can be formed from (0,1,2,3,4,5,6,7,8) without repetition?
Explanation opens after your attempt
A. (6720)
Concept
There are (4) choices (1,3,5,7) for the last place, and the first place cannot be (0). The total is \(4\cdot7\cdot{}^{7}P_3=5880\).
Why this answer is correct
The correct answer is A. (6720). There are (4) choices (1,3,5,7) for the last place, and the first place cannot be (0). The total is \(4\cdot7\cdot{}^{7}P_3=5880\).
Exam Tip
अंतिम स्थान पर (1,3,5,7) के (4) विकल्प हैं और पहला स्थान (0) नहीं हो सकता। कुल \(4\cdot7\cdot{}^{7}P_3=5880\) है।
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