पूर्णांक (x) के लिए \(-5<2x+3\le13\) में कितने हल हैं?

For integer (x), how many solutions does \(-5<2x+3\le13\) have?

Explanation opens after your attempt
Correct Answer

B. (9)

Step 1

Concept

Subtracting gives \(-8<2x\le10\), so \(-4<x\le5\). Integer solutions are from (-3) to (5), totaling (9).

Step 2

Why this answer is correct

The correct answer is B. (9). Subtracting gives \(-8<2x\le10\), so \(-4<x\le5\). Integer solutions are from (-3) to (5), totaling (9).

Step 3

Exam Tip

घटाने पर \(-8<2x\le10\), इसलिए \(-4<x\le5\) मिलता है। पूर्णांक हल (-3) से (5) तक हैं, कुल (9)।

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Mathematics Answer, Explanation and Revision Hints

पूर्णांक (x) के लिए \(-5<2x+3\le13\) में कितने हल हैं? / For integer (x), how many solutions does \(-5<2x+3\le13\) have?

Correct Answer: B. (9). Explanation: घटाने पर \(-8<2x\le10\), इसलिए \(-4<x\le5\) मिलता है। पूर्णांक हल (-3) से (5) तक हैं, कुल (9)। / Subtracting gives \(-8<2x\le10\), so \(-4<x\le5\). Integer solutions are from (-3) to (5), totaling (9).

Which concept should I revise for this Mathematics MCQ?

Subtracting gives \(-8<2x\le10\), so \(-4<x\le5\). Integer solutions are from (-3) to (5), totaling (9).

What exam hint can help solve this Mathematics question?

घटाने पर \(-8<2x\le10\), इसलिए \(-4<x\le5\) मिलता है। पूर्णांक हल (-3) से (5) तक हैं, कुल (9)।