\(यदि (U={1,2,\ldots,24}), (A={x:x\) 2 से विभाज्य है\(}), (B={x:x\) 3 से विभाज्य है\(}), (C={x:x\) 4 से विभाज्य है\(}), तो (|(A\cup B\cup C)'|) कितना है\)?
\(If (U={1,2,\ldots,24}), (A={x:x\) is divisible by \(2}), (B={x:x\) is divisible by \(3}), (C={x:x\) is divisible by \(4}), what is (|(A\cup B\cup C)'|)\)?
Explanation opens after your attempt
A. (8)
Simple Explanation
क्योंकि \(C\subseteq A\), इसलिए \(A\cup B\cup C=A\cup B\)। \(|A\cup B|=12+8-4=16\), अतः पूरक (24-16=8) है। / Since \(C\subseteq A\), \(A\cup B\cup C=A\cup B\). \(|A\cup B|=12+8-4=16\), so the complement is (24-16=8).
Login to save your score, XP, coins and progress.
QR scan karne par isi question ka correct answer aur explanation khula hua milega.
Open answer link