असमानता \(15-3x\ge 6\) का सही हल क्या है?

What is the correct solution of \(15-3x\ge 6\)?

Explanation opens after your attempt
Correct Answer

A. \(x\le 3\)

Step 1

Concept

From \(15-3x\ge 6\), we get \(-3x\ge -9\), and division by (-3) gives \(x\le 3\). Negative division changes the direction.

Step 2

Why this answer is correct

The correct answer is A. \(x\le 3\). From \(15-3x\ge 6\), we get \(-3x\ge -9\), and division by (-3) gives \(x\le 3\). Negative division changes the direction.

Step 3

Exam Tip

\(15-3x\ge 6\) से \(-3x\ge -9\) और (-3) से भाग देने पर \(x\le 3\)। ऋणात्मक भाग में दिशा बदलती है।

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Mathematics Answer, Explanation and Revision Hints

असमानता \(15-3x\ge 6\) का सही हल क्या है? / What is the correct solution of \(15-3x\ge 6\)?

Correct Answer: A. \(x\le 3\). Explanation: \(15-3x\ge 6\) से \(-3x\ge -9\) और (-3) से भाग देने पर \(x\le 3\)। ऋणात्मक भाग में दिशा बदलती है। / From \(15-3x\ge 6\), we get \(-3x\ge -9\), and division by (-3) gives \(x\le 3\). Negative division changes the direction.

Which concept should I revise for this Mathematics MCQ?

From \(15-3x\ge 6\), we get \(-3x\ge -9\), and division by (-3) gives \(x\le 3\). Negative division changes the direction.

What exam hint can help solve this Mathematics question?

\(15-3x\ge 6\) से \(-3x\ge -9\) और (-3) से भाग देने पर \(x\le 3\)। ऋणात्मक भाग में दिशा बदलती है।