Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 21-30 of 609 questions.
How many circles can be formed from (6) points if no (3) points are collinear?
C. (20)
एक वृत्त को (3) बिंदु निर्धारित करते हैं। इसलिए \(\binom{6}{3}=20\) सही है। / A circle is determined by (3) points. Hence \(\binom{6}{3}=20\) is correct.
Login to save your score, XP, coins and progress.
What is the total number of handshakes among (10) persons taken (2) at a time?
B. (45)
हर हाथ मिलाना (2) व्यक्तियों की एक जोड़ी है। इसलिए कुल संख्या \(\binom{10}{2}=45\) है। / Each handshake is a pair of (2) persons. Therefore the total number is \(\binom{10}{2}=45\).
Login to save your score, XP, coins and progress.
In how many ways can a committee of (3) members be selected from (9) members?
C. (84)
समिति चयन का प्रश्न है इसलिए \(\binom{9}{3}=84\) है। समिति में पद न हों तो क्रम नहीं गिना जाता। / This is a committee selection question, so \(\binom{9}{3}=84\). If posts are not assigned, order is not counted.
Login to save your score, XP, coins and progress.
How many ways are there to select (2) candidates for an award from (12) candidates?
B. (66)
दो समान चयनित उम्मीदवारों का क्रम महत्वपूर्ण नहीं है। अतः \(\binom{12}{2}=66\) होगा। / The order of the two selected candidates is not important. Thus \(\binom{12}{2}=66\).
Login to save your score, XP, coins and progress.
How many ways are there to choose (3) cards from (11) different cards?
C. (165)
यह \(\binom{11}{3}=165\) का सीधा प्रयोग है। कार्ड चुनने में क्रम नहीं देखा जाता। / This is a direct use of \(\binom{11}{3}=165\). Order is not considered while choosing cards.
Login to save your score, XP, coins and progress.
From (6) red balls and (4) blue balls, in how many ways can (1) red and (1) blue ball be selected?
C. (24)
तरीके \(\binom{6}{1}\binom{4}{1}=24\) हैं। अलग रंगों के चयन में गुणा नियम लगाएं। / The ways are \(\binom{6}{1}\binom{4}{1}=24\). Apply multiplication rule for selections from different colors.
Login to save your score, XP, coins and progress.
From (5) red balls and (3) black balls, how many ways are there to choose (2) red balls?
B. (10)
केवल लाल गेंदों में से चयन है। इसलिए \(\binom{5}{2}=10\) सही है। / Only red balls are being selected. Hence \(\binom{5}{2}=10\) is correct.
Login to save your score, XP, coins and progress.
How many ways are there to select (3) chairs from (7) chairs?
B. (35)
चयन में व्यवस्था नहीं करनी है इसलिए \(\binom{7}{3}=35\) है। कुर्सियां चुनना संयोजन है। / No arrangement is required, so \(\binom{7}{3}=35\). Choosing chairs is a combination.
Login to save your score, XP, coins and progress.
B. (78)
समिति के लिए केवल चयन है इसलिए \(\binom{13}{2}=78\) होगा। पद अलग न हों तो क्रम नहीं गिना जाता। / It is only selection for a committee, so \(\binom{13}{2}=78\). If posts are not different, order is not counted.
Login to save your score, XP, coins and progress.
How many ways are there to choose (4) subjects from (6) subjects?
C. (15)
\(\binom{6}{4}=\binom{6}{2}=15\) होता है। \(\binom{n}{r}=\binom{n}{n-r}\) याद रखें। / \(\binom{6}{4}=\binom{6}{2}=15\). Remember \(\binom{n}{r}=\binom{n}{n-r}\).
Login to save your score, XP, coins and progress.
Use Google login or mobile OTP. Admin can block users and control login providers.