Restriction Enzymes

Correct answer: D. starch cooking

Restriction enzymes are useful in DNA-related techniques. Starch cooking is not their application.

Correct answer: A. Restriction enzyme can cut the vector

A restriction enzyme is useful to open a cloning vector for an insert. This is a basic step in cloning.

Correct answer: A. Directional cloning with two different enzymes

Two different incompatible ends can reduce vector self-ligation. This is useful in cloning strategy.

Correct answer: A. base pairing

Complementary sticky ends can base pair through hydrogen bonding. DNA ligase is needed for permanent joining.

Correct answer: A. phosphodiester bond

Restriction enzymes cut phosphodiester bonds in the sugar-phosphate backbone of DNA. This fact is linked with DNA structure.

Correct answer: A. Heat can reduce activity

Restriction enzymes are proteins, so their three-dimensional structure is essential for substrate recognition and catalysis. Excessive heat can disrupt weak interactions that maintain this structure, causing denaturation and a reduction or loss of enzymatic activity. The effect depends on the enzyme and exposure conditions, but the general implication in laboratory work is that temperature must be controlled. Option A is therefore correct. Restriction enzymes are not metals, and their defining function is recognition of specific DNA sequences. Like other proteins, they can become inactive under unsuitable temperature, pH, salt, or storage conditions, making options B, C, and D incorrect.

Correct answer: A. About 37 degrees Celsius

Many bacterial enzymes are active around 37 degrees Celsius. However the exact optimum can be enzyme-specific.

Correct answer: A. Giving enzyme time to cut DNA

During incubation the enzyme acts on DNA under suitable conditions. Time and temperature are practical factors.

Correct answer: A. Because a shorter sequence can be statistically more frequent

Short recognition sequences can occur more often than longer sequences. This can lead to more cut sites.

Correct answer: A. Give less frequent sites

A longer recognition sequence is less likely to occur frequently. This can affect the number of fragments.

Correct answer: A. DNA will not be cut properly

An inactive enzyme cannot cut even if the recognition site is present. Activity is a basic requirement of restriction digestion.

Correct answer: A. incomplete digestion

If an uncut band appears some plasmid molecules may not have been cut. This can indicate incomplete digestion.

Correct answer: A. DNA fragment analysis

First the restriction enzyme cuts DNA and then gel electrophoresis separates fragments. Both are linked in DNA analysis.

Correct answer: A. They cut DNA molecules

The name molecular scissors comes from their DNA cutting function. This is a basic term in Class 11 biotechnology.

Correct answer: A. Many restriction enzymes recognize palindromic DNA sites

Many recognition sites are palindromic. This is linked with sequence recognition by restriction enzymes.

Correct answer: A. Methylase and methylation

The direct answer is A: methylase and methylation protect bacterial DNA. Bacteria may produce restriction enzymes to cut foreign DNA, such as invading phage DNA. To avoid cutting their own genome, a methylase adds methyl groups to particular bases in the bacterium’s DNA. This methylation marks self DNA and prevents the matching restriction enzyme from recognizing or cutting it, or otherwise protects the site. Option A is correct because it names both the enzyme and the protective modification. Option B is wrong: amylase digests starch and is not the usual protection system for restriction sites. Option C is wrong: lipase breaks down fats and has no role in marking bacterial DNA. Option D is wrong: chlorophyll and sunlight are associated with photosynthesis, not restriction-modification protection. The system works as a pair: restriction enzyme cuts unprotected foreign DNA, while methyltransferase or methylase modifies self DNA. Memory cue: methylation marks “self”; restriction cuts “foreign.”

Correct answer: A. It can cut foreign DNA

If foreign DNA is not methylated the restriction enzyme can recognize and cut it. This is part of bacterial defense.

Correct answer: A. EcoRI BamHI HindIII are common examples

EcoRI BamHI and HindIII are common examples of restriction enzymes. The other options are not DNA-cutting restriction enzymes.

Correct answer: A. pH temperature and buffer condition

Enzymes can be sensitive to reaction conditions. pH temperature and buffer can affect activity.

Correct answer: A. Cutting DNA and use in gene cloning

Restriction enzymes cut DNA and are useful in gene cloning. This is the central link of the topic.

Correct answer: A. Which sequence does EcoRI recognize

A question about the recognition sequence of EcoRI is strongly exam-oriented because it tests a standard, specific fact from molecular biotechnology. EcoRI recognizes the palindromic sequence 5′-GAATTC-3′ and cleaves within this site to produce compatible sticky ends. Such enzyme–sequence matching is frequently used in direct-recall and application-based questions about restriction digestion and recombinant-DNA construction. The other choices concern everyday observations that are not central to restriction enzymes or their laboratory use. Therefore option A is the relevant examination question. Students should learn both the enzyme name and its recognition sequence rather than memorising only the general idea of DNA cutting.

Correct answer: A. Restriction enzyme cuts vector then insert is ligated

The direct answer is option A: the restriction enzyme cuts the vector, and the insert is then joined to it by DNA ligase. A vector is a DNA carrier, commonly a plasmid, used to carry a desired gene into a host cell. First, the chosen restriction enzyme recognizes a particular DNA sequence and cuts the vector. The insert is prepared with compatible ends. The insert is placed with the cut vector, and DNA ligase seals the sugar-phosphate backbone. Option A is correct because it gives the normal order. Option B is wrong because an insert does not first become protein; it must first be joined to a vector. Option C is biologically meaningless because a vector does not become water. Option D reverses and confuses enzyme and DNA events; DNA is not formed after an enzyme simply ends. Memory cue: cut first, join second—restriction enzyme cuts and ligase joins.

Correct answer: A. Both ends of insert are same compatible type

Direct answer: A, both ends of the insert are the same compatible type. DNA ends produced by restriction enzymes can be sticky, meaning they have matching single-stranded overhangs. If the two ends of an insert are compatible with the corresponding vector ends in the same way, either end of the insert can enter either vector end. Thus the insert may join in its normal orientation or in the reverse orientation; this is called non-directional cloning. Option A is correct because identical compatible ends do not provide orientation control. Option B is wrong because an insert with no DNA cannot provide a cloned fragment. Option C is wrong because an uncut vector generally lacks the prepared compatible ends and is not ready for efficient insertion. Option D is wrong because ligase is needed to seal the joined DNA; without it, stable joining is greatly reduced. Directional cloning uses different ends at the two sides to force one orientation. Memory cue: same ends allow two directions; different ends guide one direction.

Correct answer: A. Restriction enzyme can cut internally at specific sites

Restriction enzymes cut internally like endonucleases. Exonucleases remove nucleotides from nucleic acid ends.

Correct answer: A. linear DNA fragments equal cuts plus one / Linear DNA fragments equal cuts plus one

In linear DNA after complete digestion fragments are one more than cuts. Apply this in simple mapping MCQs.