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Mathematics Quiz - Class 10 Mathematics Easy Level 67 Quiz

Question 1/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $2,5,8,\ldots$ के पहले (10) पदों का योग क्या है?

What is the sum of the first (10) terms of the AP $2,5,8,\ldots$?

Explanation opens after your attempt

Correct Answer

C. (155)

Step 1

Concept

Here (a=2), (d=3), (n=10). $S_{10}=\frac{10}{2}[2\cdot2+9\cdot3]=155$.

Step 2

Why this answer is correct

The correct answer is C. (155). Here (a=2), (d=3), (n=10). $S_{10}=\frac{10}{2}[2\cdot2+9\cdot3]=155$.

Step 3

Exam Tip

यहां (a=2), (d=3), (n=10)। $S_{10}=\frac{10}{2}[2\cdot2+9\cdot3]=155$।

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Question 2/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $4,8,12,\ldots$ के पहले (15) पदों का योग ज्ञात कीजिए।

Find the sum of the first (15) terms of the AP $4,8,12,\ldots$.

Explanation opens after your attempt

Correct Answer

A. (480)

Step 1

Concept

Here (a=4) and (d=4). $S_{15}=\frac{15}{2}[8+14\cdot4]=480$.

Step 2

Why this answer is correct

The correct answer is A. (480). Here (a=4) and (d=4). $S_{15}=\frac{15}{2}[8+14\cdot4]=480$.

Step 3

Exam Tip

यहां (a=4) और (d=4) है। $S_{15}=\frac{15}{2}[8+14\cdot4]=480$।

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Question 3/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

यदि (a=6), (d=2), (n=20) है तो $S_n$ क्या होगा?

If (a=6), (d=2), (n=20), what is $S_n$?

Explanation opens after your attempt

Correct Answer

B. (500)

Step 1

Concept

Use (S_n=\frac{n}{2}[2a+(n-1)d]). $S_{20}=10[12+38]=500$.

Step 2

Why this answer is correct

The correct answer is B. (500). Use (S_n=\frac{n}{2}[2a+(n-1)d]). $S_{20}=10[12+38]=500$.

Step 3

Exam Tip

(S_n=\frac{n}{2}[2a+(n-1)d]) लगाएं। $S_{20}=10[12+38]=500$।

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Question 4/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $1,3,5,\ldots$ के पहले (25) पदों का योग क्या है?

What is the sum of the first (25) terms of the AP $1,3,5,\ldots$?

Explanation opens after your attempt

Correct Answer

C. (625)

Step 1

Concept

The sum of the first (n) odd numbers is $n^2$. So $S_{25}=25^2=625$.

Step 2

Why this answer is correct

The correct answer is C. (625). The sum of the first (n) odd numbers is $n^2$. So $S_{25}=25^2=625$.

Step 3

Exam Tip

पहले (n) विषम संख्याओं का योग $n^2$ होता है। इसलिए $S_{25}=25^2=625$।

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Question 5/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $10,20,30,\ldots$ के पहले (12) पदों का योग कितना है?

What is the sum of the first (12) terms of the AP $10,20,30,\ldots$?

Explanation opens after your attempt

Correct Answer

B. (780)

Step 1

Concept

Here (a=10), (d=10), (n=12). $S_{12}=6[20+110]=780$.

Step 2

Why this answer is correct

The correct answer is B. (780). Here (a=10), (d=10), (n=12). $S_{12}=6[20+110]=780$.

Step 3

Exam Tip

यहां (a=10), (d=10), (n=12)। $S_{12}=6[20+110]=780$।

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Question 6/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $7,14,21,\ldots$ के पहले (10) पदों का योग क्या होगा?

What will be the sum of the first (10) terms of the AP $7,14,21,\ldots$?

Explanation opens after your attempt

Correct Answer

C. (385)

Step 1

Concept

This is the sequence of multiples of (7). (S_{10}=\frac{10}{2}(7+70)=385).

Step 2

Why this answer is correct

The correct answer is C. (385). This is the sequence of multiples of (7). (S_{10}=\frac{10}{2}(7+70)=385).

Step 3

Exam Tip

यह (7) के गुणजों की श्रेणी है। (S_{10}=\frac{10}{2}(7+70)=385)।

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Question 7/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

यदि किसी AP का पहला पद (5), अंतिम पद (45) और पदों की संख्या (9) है तो योग क्या है?

If the first term of an AP is (5), the last term is (45), and the number of terms is (9), what is the sum?

Explanation opens after your attempt

Correct Answer

B. (225)

Step 1

Concept

When first and last terms are given use (S_n=\frac{n}{2}(a+l)). (S_9=\frac{9}{2}(5+45)=225).

Step 2

Why this answer is correct

The correct answer is B. (225). When first and last terms are given use (S_n=\frac{n}{2}(a+l)). (S_9=\frac{9}{2}(5+45)=225).

Step 3

Exam Tip

जब पहला और अंतिम पद दिए हों तो (S_n=\frac{n}{2}(a+l))। (S_9=\frac{9}{2}(5+45)=225)।

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Question 8/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $3,6,9,\ldots$ के पहले (30) पदों का योग ज्ञात कीजिए।

Find the sum of the first (30) terms of the AP $3,6,9,\ldots$.

Explanation opens after your attempt

Correct Answer

A. (1395)

Step 1

Concept

Here the last term is (90). (S_{30}=\frac{30}{2}(3+90)=1395).

Step 2

Why this answer is correct

The correct answer is A. (1395). Here the last term is (90). (S_{30}=\frac{30}{2}(3+90)=1395).

Step 3

Exam Tip

यहां अंतिम पद (90) है। (S_{30}=\frac{30}{2}(3+90)=1395)।

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Question 9/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $20,18,16,\ldots$ के पहले (8) पदों का योग क्या है?

What is the sum of the first (8) terms of the AP $20,18,16,\ldots$?

Explanation opens after your attempt

Correct Answer

B. (104)

Step 1

Concept

This is a decreasing AP with (d=-2). (S_8=\frac{8}{2}[40+7(-2)]=104).

Step 2

Why this answer is correct

The correct answer is B. (104). This is a decreasing AP with (d=-2). (S_8=\frac{8}{2}[40+7(-2)]=104).

Step 3

Exam Tip

यह घटती AP है जिसमें (d=-2) है। (S_8=\frac{8}{2}[40+7(-2)]=104)।

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Question 10/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

यदि AP $9,13,17,\ldots$ है तो पहले (11) पदों का योग क्या है?

If the AP is $9,13,17,\ldots$, what is the sum of the first (11) terms?

Explanation opens after your attempt

Correct Answer

A. (319)

Step 1

Concept

Here (a=9), (d=4), (n=11). $S_{11}=\frac{11}{2}[18+40]=319$.

Step 2

Why this answer is correct

The correct answer is A. (319). Here (a=9), (d=4), (n=11). $S_{11}=\frac{11}{2}[18+40]=319$.

Step 3

Exam Tip

यहां (a=9), (d=4), (n=11)। $S_{11}=\frac{11}{2}[18+40]=319$।

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Question 11/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $12,17,22,\ldots$ के पहले (14) पदों का योग कितना है?

What is the sum of the first (14) terms of the AP $12,17,22,\ldots$?

Explanation opens after your attempt

Correct Answer

C. (623)

Step 1

Concept

The last term is $12+13\cdot5=77$. (S_{14}=\frac{14}{2}(12+77)=623).

Step 2

Why this answer is correct

The correct answer is C. (623). The last term is $12+13\cdot5=77$. (S_{14}=\frac{14}{2}(12+77)=623).

Step 3

Exam Tip

अंतिम पद $12+13\cdot5=77$ है। (S_{14}=\frac{14}{2}(12+77)=623)।

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Question 12/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $5,10,15,\ldots$ के पहले (18) पदों का योग क्या होगा?

What will be the sum of the first (18) terms of the AP $5,10,15,\ldots$?

Explanation opens after your attempt

Correct Answer

B. (855)

Step 1

Concept

Here the last term is (90). (S_{18}=\frac{18}{2}(5+90)=855).

Step 2

Why this answer is correct

The correct answer is B. (855). Here the last term is (90). (S_{18}=\frac{18}{2}(5+90)=855).

Step 3

Exam Tip

यहां अंतिम पद (90) है। (S_{18}=\frac{18}{2}(5+90)=855)।

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Question 13/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

यदि (a=8), (d=3), (n=16) है तो $S_{16}$ कितना होगा?

If (a=8), (d=3), (n=16), what is $S_{16}$?

Explanation opens after your attempt

Correct Answer

A. (488)

Step 1

Concept

$S_{16}=\frac{16}{2}[16+15\cdot3]$. Therefore $S_{16}=8\cdot61=488$.

Step 2

Why this answer is correct

The correct answer is A. (488). $S_{16}=\frac{16}{2}[16+15\cdot3]$. Therefore $S_{16}=8\cdot61=488$.

Step 3

Exam Tip

$S_{16}=\frac{16}{2}[16+15\cdot3]$। इसलिए $S_{16}=8\cdot61=488$।

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Question 14/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $6,11,16,\ldots$ के पहले (9) पदों का योग क्या है?

What is the sum of the first (9) terms of the AP $6,11,16,\ldots$?

Explanation opens after your attempt

Correct Answer

B. (234)

Step 1

Concept

$a_9=6+8\cdot5=46$. (S_9=\frac{9}{2}(6+46)=234).

Step 2

Why this answer is correct

The correct answer is B. (234). $a_9=6+8\cdot5=46$. (S_9=\frac{9}{2}(6+46)=234).

Step 3

Exam Tip

$a_9=6+8\cdot5=46$ है। (S_9=\frac{9}{2}(6+46)=234)।

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Question 15/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

पहले (20) प्राकृतिक संख्याओं का योग क्या है?

What is the sum of the first (20) natural numbers?

Explanation opens after your attempt

Correct Answer

C. (210)

Step 1

Concept

For natural numbers (S_n=\frac{n(n+1)}{2}). $S_{20}=\frac{20\cdot21}{2}=210$.

Step 2

Why this answer is correct

The correct answer is C. (210). For natural numbers (S_n=\frac{n(n+1)}{2}). $S_{20}=\frac{20\cdot21}{2}=210$.

Step 3

Exam Tip

प्राकृतिक संख्याओं के लिए (S_n=\frac{n(n+1)}{2})। $S_{20}=\frac{20\cdot21}{2}=210$।

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Question 16/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

पहले (16) सम प्राकृतिक संख्याओं का योग कितना है?

What is the sum of the first (16) even natural numbers?

Explanation opens after your attempt

Correct Answer

A. (272)

Step 1

Concept

The sum of the first (n) even numbers is (n(n+1)). $16\cdot17=272$.

Step 2

Why this answer is correct

The correct answer is A. (272). The sum of the first (n) even numbers is (n(n+1)). $16\cdot17=272$.

Step 3

Exam Tip

पहली (n) सम संख्याओं का योग (n(n+1)) होता है। $16\cdot17=272$।

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Question 17/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $15,25,35,\ldots$ के पहले (13) पदों का योग क्या है?

What is the sum of the first (13) terms of the AP $15,25,35,\ldots$?

Explanation opens after your attempt

Correct Answer

C. (975)

Step 1

Concept

The last term is $15+12\cdot10=135$. (S_{13}=\frac{13}{2}(15+135)=975).

Step 2

Why this answer is correct

The correct answer is C. (975). The last term is $15+12\cdot10=135$. (S_{13}=\frac{13}{2}(15+135)=975).

Step 3

Exam Tip

अंतिम पद $15+12\cdot10=135$ है। (S_{13}=\frac{13}{2}(15+135)=975)।

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Question 18/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

यदि पहले (n) पदों का योग (S_n=\frac{n}{2}(3n+1)) है तो $S_{10}$ क्या होगा?

If the sum of the first (n) terms is (S_n=\frac{n}{2}(3n+1)), what is $S_{10}$?

Explanation opens after your attempt

Correct Answer

B. (155)

Step 1

Concept

Put (n=10) in the formula. (S_{10}=\frac{10}{2}(31)=155).

Step 2

Why this answer is correct

The correct answer is B. (155). Put (n=10) in the formula. (S_{10}=\frac{10}{2}(31)=155).

Step 3

Exam Tip

सूत्र में (n=10) रखें। (S_{10}=\frac{10}{2}(31)=155)।

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Question 19/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $30,27,24,\ldots$ के पहले (10) पदों का योग ज्ञात कीजिए।

Find the sum of the first (10) terms of the AP $30,27,24,\ldots$.

Explanation opens after your attempt

Correct Answer

C. (165)

Step 1

Concept

Here (d=-3). (S_{10}=5[60+9(-3)]=165).

Step 2

Why this answer is correct

The correct answer is C. (165). Here (d=-3). (S_{10}=5[60+9(-3)]=165).

Step 3

Exam Tip

यहां (d=-3) है। (S_{10}=5[60+9(-3)]=165)।

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Question 20/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

एक AP का (a=2), (l=38) और (n=10) है। $S_n$ क्या होगा?

An AP has (a=2), (l=38), and (n=10). What is $S_n$?

Explanation opens after your attempt

Correct Answer

C. (200)

Step 1

Concept

The first and last terms are given. (S_{10}=\frac{10}{2}(2+38)=200).

Step 2

Why this answer is correct

The correct answer is C. (200). The first and last terms are given. (S_{10}=\frac{10}{2}(2+38)=200).

Step 3

Exam Tip

पहला और अंतिम पद दिए हैं। (S_{10}=\frac{10}{2}(2+38)=200)।

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Question 21/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $11,22,33,\ldots$ के पहले (9) पदों का योग कितना है?

What is the sum of the first (9) terms of the AP $11,22,33,\ldots$?

Explanation opens after your attempt

Correct Answer

B. (495)

Step 1

Concept

The last term is (99). (S_9=\frac{9}{2}(11+99)=495).

Step 2

Why this answer is correct

The correct answer is B. (495). The last term is (99). (S_9=\frac{9}{2}(11+99)=495).

Step 3

Exam Tip

अंतिम पद (99) है। (S_9=\frac{9}{2}(11+99)=495)।

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Question 22/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $13,16,19,\ldots$ के पहले (12) पदों का योग क्या है?

What is the sum of the first (12) terms of the AP $13,16,19,\ldots$?

Explanation opens after your attempt

Correct Answer

A. (354)

Step 1

Concept

The last term is $13+11\cdot3=46$. (S_{12}=\frac{12}{2}(13+46)=354).

Step 2

Why this answer is correct

The correct answer is A. (354). The last term is $13+11\cdot3=46$. (S_{12}=\frac{12}{2}(13+46)=354).

Step 3

Exam Tip

अंतिम पद $13+11\cdot3=46$ है। (S_{12}=\frac{12}{2}(13+46)=354)।

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Question 23/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

यदि (a=25), (d=-2), (n=15) है तो $S_{15}$ क्या होगा?

If (a=25), (d=-2), (n=15), what is $S_{15}$?

Explanation opens after your attempt

Correct Answer

C. (165)

Step 1

Concept

In a decreasing AP use (d=-2). (S_{15}=\frac{15}{2}[50+14(-2)]=165).

Step 2

Why this answer is correct

The correct answer is C. (165). In a decreasing AP use (d=-2). (S_{15}=\frac{15}{2}[50+14(-2)]=165).

Step 3

Exam Tip

घटती AP में (d=-2) रखें। (S_{15}=\frac{15}{2}[50+14(-2)]=165)।

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Question 24/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $18,21,24,\ldots$ के पहले (20) पदों का योग कितना होगा?

What will be the sum of the first (20) terms of the AP $18,21,24,\ldots$?

Explanation opens after your attempt

Correct Answer

C. (930)

Step 1

Concept

The last term is $18+19\cdot3=75$. (S_{20}=\frac{20}{2}(18+75)=930).

Step 2

Why this answer is correct

The correct answer is C. (930). The last term is $18+19\cdot3=75$. (S_{20}=\frac{20}{2}(18+75)=930).

Step 3

Exam Tip

अंतिम पद $18+19\cdot3=75$ है। (S_{20}=\frac{20}{2}(18+75)=930)।

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Question 25/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $40,35,30,\ldots$ के पहले (7) पदों का योग क्या है?

What is the sum of the first (7) terms of the AP $40,35,30,\ldots$?

Explanation opens after your attempt

Correct Answer

C. (175)

Step 1

Concept

The last term is (40+6(-5)=10). (S_7=\frac{7}{2}(40+10)=175).

Step 2

Why this answer is correct

The correct answer is C. (175). The last term is (40+6(-5)=10). (S_7=\frac{7}{2}(40+10)=175).

Step 3

Exam Tip

अंतिम पद (40+6(-5)=10) है। (S_7=\frac{7}{2}(40+10)=175)।

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Question 26/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

एक AP में (n=8), (a=4) और (l=32) है। योग क्या है?

In an AP (n=8), (a=4), and (l=32). What is the sum?

Explanation opens after your attempt

Correct Answer

C. (144)

Step 1

Concept

Use (S_n=\frac{n}{2}(a+l)). (S_8=\frac{8}{2}(4+32)=144).

Step 2

Why this answer is correct

The correct answer is C. (144). Use (S_n=\frac{n}{2}(a+l)). (S_8=\frac{8}{2}(4+32)=144).

Step 3

Exam Tip

(S_n=\frac{n}{2}(a+l)) लगाएं। (S_8=\frac{8}{2}(4+32)=144)।

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Question 27/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $2,4,6,\ldots$ के पहले (50) पदों का योग क्या है?

What is the sum of the first (50) terms of the AP $2,4,6,\ldots$?

Explanation opens after your attempt

Correct Answer

B. (2550)

Step 1

Concept

The sum of the first (n) even terms is (n(n+1)). $50\cdot51=2550$.

Step 2

Why this answer is correct

The correct answer is B. (2550). The sum of the first (n) even terms is (n(n+1)). $50\cdot51=2550$.

Step 3

Exam Tip

पहले (n) सम पदों का योग (n(n+1)) है। $50\cdot51=2550$।

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Question 28/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $9,18,27,\ldots$ के पहले (12) पदों का योग कितना है?

What is the sum of the first (12) terms of the AP $9,18,27,\ldots$?

Explanation opens after your attempt

Correct Answer

B. (702)

Step 1

Concept

The last term is (108). (S_{12}=\frac{12}{2}(9+108)=702).

Step 2

Why this answer is correct

The correct answer is B. (702). The last term is (108). (S_{12}=\frac{12}{2}(9+108)=702).

Step 3

Exam Tip

अंतिम पद (108) है। (S_{12}=\frac{12}{2}(9+108)=702)।

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Question 29/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $100,90,80,\ldots$ के पहले (6) पदों का योग क्या है?

What is the sum of the first (6) terms of the AP $100,90,80,\ldots$?

Explanation opens after your attempt

Correct Answer

C. (450)

Step 1

Concept

The sixth term is (50). (S_6=\frac{6}{2}(100+50)=450).

Step 2

Why this answer is correct

The correct answer is C. (450). The sixth term is (50). (S_6=\frac{6}{2}(100+50)=450).

Step 3

Exam Tip

छठा पद (50) है। (S_6=\frac{6}{2}(100+50)=450)।

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Question 30/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

यदि (S_n=\frac{n}{2}(2n+4)) है तो $S_{12}$ क्या होगा?

If (S_n=\frac{n}{2}(2n+4)), what is $S_{12}$?

Explanation opens after your attempt

Correct Answer

C. (168)

Step 1

Concept

Put (n=12) in the formula. (S_{12}=\frac{12}{2}(24+4)=168).

Step 2

Why this answer is correct

The correct answer is C. (168). Put (n=12) in the formula. (S_{12}=\frac{12}{2}(24+4)=168).

Step 3

Exam Tip

सूत्र में (n=12) रखें। (S_{12}=\frac{12}{2}(24+4)=168)।

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Question 31/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $16,24,32,\ldots$ के पहले (10) पदों का योग क्या होगा?

What will be the sum of the first (10) terms of the AP $16,24,32,\ldots$?

Explanation opens after your attempt

Correct Answer

C. (520)

Step 1

Concept

The tenth term is (88). (S_{10}=\frac{10}{2}(16+88)=520).

Step 2

Why this answer is correct

The correct answer is C. (520). The tenth term is (88). (S_{10}=\frac{10}{2}(16+88)=520).

Step 3

Exam Tip

दसवां पद (88) है। (S_{10}=\frac{10}{2}(16+88)=520)।

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Question 32/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

एक AP के पहले (5) पद (3,7,11,15,19) हैं। इनका योग क्या है?

The first (5) terms of an AP are (3,7,11,15,19). What is their sum?

Explanation opens after your attempt

Correct Answer

A. (55)

Step 1

Concept

Adding directly (3+7+11+15+19=55). For small (n), direct addition is useful too.

Step 2

Why this answer is correct

The correct answer is A. (55). Adding directly (3+7+11+15+19=55). For small (n), direct addition is useful too.

Step 3

Exam Tip

सीधे जोड़ने पर (3+7+11+15+19=55)। छोटे (n) में सीधा जोड़ भी उपयोगी है।

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Question 33/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $21,28,35,\ldots$ के पहले (8) पदों का योग कितना है?

What is the sum of the first (8) terms of the AP $21,28,35,\ldots$?

Explanation opens after your attempt

Correct Answer

B. (364)

Step 1

Concept

The eighth term is (70). (S_8=\frac{8}{2}(21+70)=364).

Step 2

Why this answer is correct

The correct answer is B. (364). The eighth term is (70). (S_8=\frac{8}{2}(21+70)=364).

Step 3

Exam Tip

आठवां पद (70) है। (S_8=\frac{8}{2}(21+70)=364)।

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Question 34/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

यदि (a=1), (d=1), (n=100) है तो $S_{100}$ क्या होगा?

If (a=1), (d=1), (n=100), what is $S_{100}$?

Explanation opens after your attempt

Correct Answer

B. (5050)

Step 1

Concept

This is the sum of the first (100) natural numbers. $S_{100}=\frac{100\cdot101}{2}=5050$.

Step 2

Why this answer is correct

The correct answer is B. (5050). This is the sum of the first (100) natural numbers. $S_{100}=\frac{100\cdot101}{2}=5050$.

Step 3

Exam Tip

यह पहले (100) प्राकृतिक संख्याओं का योग है। $S_{100}=\frac{100\cdot101}{2}=5050$।

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Question 35/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $50,45,40,\ldots$ के पहले (9) पदों का योग क्या है?

What is the sum of the first (9) terms of the AP $50,45,40,\ldots$?

Explanation opens after your attempt

Correct Answer

B. (270)

Step 1

Concept

The ninth term is (10). (S_9=\frac{9}{2}(50+10)=270).

Step 2

Why this answer is correct

The correct answer is B. (270). The ninth term is (10). (S_9=\frac{9}{2}(50+10)=270).

Step 3

Exam Tip

नौवां पद (10) है। (S_9=\frac{9}{2}(50+10)=270)।

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Question 36/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $0,4,8,\ldots$ के पहले (11) पदों का योग ज्ञात कीजिए।

Find the sum of the first (11) terms of the AP $0,4,8,\ldots$.

Explanation opens after your attempt

Correct Answer

B. (220)

Step 1

Concept

The last term is (40). (S_{11}=\frac{11}{2}(0+40)=220).

Step 2

Why this answer is correct

The correct answer is B. (220). The last term is (40). (S_{11}=\frac{11}{2}(0+40)=220).

Step 3

Exam Tip

अंतिम पद (40) है। (S_{11}=\frac{11}{2}(0+40)=220)।

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Question 37/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

यदि (a=3), (d=6), (n=12) है तो पहले (12) पदों का योग क्या है?

If (a=3), (d=6), (n=12), what is the sum of the first (12) terms?

Explanation opens after your attempt

Correct Answer

A. (432)

Step 1

Concept

$S_{12}=\frac{12}{2}[6+11\cdot6]$. Therefore $S_{12}=6\cdot72=432$.

Step 2

Why this answer is correct

The correct answer is A. (432). $S_{12}=\frac{12}{2}[6+11\cdot6]$. Therefore $S_{12}=6\cdot72=432$.

Step 3

Exam Tip

$S_{12}=\frac{12}{2}[6+11\cdot6]$। इसलिए $S_{12}=6\cdot72=432$।

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Question 38/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $14,18,22,\ldots$ के पहले (25) पदों का योग कितना है?

What is the sum of the first (25) terms of the AP $14,18,22,\ldots$?

Explanation opens after your attempt

Correct Answer

B. (1550)

Step 1

Concept

The last term is $14+24\cdot4=110$. (S_{25}=\frac{25}{2}(14+110)=1550).

Step 2

Why this answer is correct

The correct answer is B. (1550). The last term is $14+24\cdot4=110$. (S_{25}=\frac{25}{2}(14+110)=1550).

Step 3

Exam Tip

अंतिम पद $14+24\cdot4=110$ है। (S_{25}=\frac{25}{2}(14+110)=1550)।

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Question 39/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

एक AP में पहला पद (12), अंतिम पद (72) और कुल पद (11) हैं। योग क्या होगा?

In an AP, the first term is (12), the last term is (72), and total terms are (11). What is the sum?

Explanation opens after your attempt

Correct Answer

C. (462)

Step 1

Concept

Using (S_n=\frac{n}{2}(a+l)), (S_{11}=\frac{11}{2}(12+72)=462).

Step 2

Why this answer is correct

The correct answer is C. (462). Using (S_n=\frac{n}{2}(a+l)), (S_{11}=\frac{11}{2}(12+72)=462).

Step 3

Exam Tip

(S_n=\frac{n}{2}(a+l)) से (S_{11}=\frac{11}{2}(12+72)=462)।

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Question 40/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $24,30,36,\ldots$ के पहले (16) पदों का योग क्या है?

What is the sum of the first (16) terms of the AP $24,30,36,\ldots$?

Explanation opens after your attempt

Correct Answer

C. (1104)

Step 1

Concept

The sixteenth term is (114). (S_{16}=\frac{16}{2}(24+114)=1104).

Step 2

Why this answer is correct

The correct answer is C. (1104). The sixteenth term is (114). (S_{16}=\frac{16}{2}(24+114)=1104).

Step 3

Exam Tip

सोलहवां पद (114) है। (S_{16}=\frac{16}{2}(24+114)=1104)।

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Question 41/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

पहले (15) विषम प्राकृतिक संख्याओं का योग क्या है?

What is the sum of the first (15) odd natural numbers?

Explanation opens after your attempt

Correct Answer

B. (225)

Step 1

Concept

The sum of the first (n) odd numbers is $n^2$. $15^2=225$.

Step 2

Why this answer is correct

The correct answer is B. (225). The sum of the first (n) odd numbers is $n^2$. $15^2=225$.

Step 3

Exam Tip

पहले (n) विषम संख्याओं का योग $n^2$ है। $15^2=225$।

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Question 42/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $17,22,27,\ldots$ के पहले (10) पदों का योग कितना है?

What is the sum of the first (10) terms of the AP $17,22,27,\ldots$?

Explanation opens after your attempt

Correct Answer

C. (395)

Step 1

Concept

The tenth term is (62). (S_{10}=\frac{10}{2}(17+62)=395).

Step 2

Why this answer is correct

The correct answer is C. (395). The tenth term is (62). (S_{10}=\frac{10}{2}(17+62)=395).

Step 3

Exam Tip

दसवां पद (62) है। (S_{10}=\frac{10}{2}(17+62)=395)।

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Question 43/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

यदि $S_n=2n^2+n$ है तो $S_9$ क्या होगा?

If $S_n=2n^2+n$, what is $S_9$?

Explanation opens after your attempt

Correct Answer

A. (171)

Step 1

Concept

Put (n=9) in the formula. $S_9=2\cdot9^2+9=171$.

Step 2

Why this answer is correct

The correct answer is A. (171). Put (n=9) in the formula. $S_9=2\cdot9^2+9=171$.

Step 3

Exam Tip

सूत्र में (n=9) रखें। $S_9=2\cdot9^2+9=171$।

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Question 44/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $60,54,48,\ldots$ के पहले (5) पदों का योग क्या होगा?

What will be the sum of the first (5) terms of the AP $60,54,48,\ldots$?

Explanation opens after your attempt

Correct Answer

B. (240)

Step 1

Concept

The fifth term is (36). (S_5=\frac{5}{2}(60+36)=240).

Step 2

Why this answer is correct

The correct answer is B. (240). The fifth term is (36). (S_5=\frac{5}{2}(60+36)=240).

Step 3

Exam Tip

पांचवां पद (36) है। (S_5=\frac{5}{2}(60+36)=240)।

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Question 45/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $8,16,24,\ldots$ के पहले (14) पदों का योग कितना है?

What is the sum of the first (14) terms of the AP $8,16,24,\ldots$?

Explanation opens after your attempt

Correct Answer

C. (840)

Step 1

Concept

The fourteenth term is (112). (S_{14}=\frac{14}{2}(8+112)=840).

Step 2

Why this answer is correct

The correct answer is C. (840). The fourteenth term is (112). (S_{14}=\frac{14}{2}(8+112)=840).

Step 3

Exam Tip

चौदहवां पद (112) है। (S_{14}=\frac{14}{2}(8+112)=840)।

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Question 46/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

एक AP में (a=11), (d=11), (n=20) है। योग क्या है?

In an AP (a=11), (d=11), (n=20). What is the sum?

Explanation opens after your attempt

Correct Answer

A. (2310)

Step 1

Concept

This is the sum of the first (20) multiples of (11). (S_{20}=\frac{20}{2}(11+220)=2310).

Step 2

Why this answer is correct

The correct answer is A. (2310). This is the sum of the first (20) multiples of (11). (S_{20}=\frac{20}{2}(11+220)=2310).

Step 3

Exam Tip

यह (11) के पहले (20) गुणजों का योग है। (S_{20}=\frac{20}{2}(11+220)=2310)।

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Question 47/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $5,9,13,\ldots$ के पहले (18) पदों का योग क्या होगा?

What will be the sum of the first (18) terms of the AP $5,9,13,\ldots$?

Explanation opens after your attempt

Correct Answer

D. (702)

Step 1

Concept

The eighteenth term is $5+17\cdot4=73$. (S_{18}=\frac{18}{2}(5+73)=702).

Step 2

Why this answer is correct

The correct answer is D. (702). The eighteenth term is $5+17\cdot4=73$. (S_{18}=\frac{18}{2}(5+73)=702).

Step 3

Exam Tip

अठारहवां पद $5+17\cdot4=73$ है। (S_{18}=\frac{18}{2}(5+73)=702)।

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Question 48/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

यदि (a=7), (d=0), (n=12) है तो $S_{12}$ क्या होगा?

If (a=7), (d=0), (n=12), what is $S_{12}$?

Explanation opens after your attempt

Correct Answer

A. (84)

Step 1

Concept

All (12) terms are (7). Therefore $S_{12}=12\times7=84$.

Step 2

Why this answer is correct

The correct answer is A. (84). All (12) terms are (7). Therefore $S_{12}=12\times7=84$.

Step 3

Exam Tip

सभी (12) पद (7) हैं। इसलिए $S_{12}=12\times7=84$।

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Question 49/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $19,29,39,\ldots$ के पहले (6) पदों का योग क्या है?

What is the sum of the first (6) terms of the AP $19,29,39,\ldots$?

Explanation opens after your attempt

Correct Answer

A. (264)

Step 1

Concept

The sixth term is (69). (S_6=\frac{6}{2}(19+69)=264).

Step 2

Why this answer is correct

The correct answer is A. (264). The sixth term is (69). (S_6=\frac{6}{2}(19+69)=264).

Step 3

Exam Tip

छठा पद (69) है। (S_6=\frac{6}{2}(19+69)=264)।

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Question 50/50 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

समान्तर श्रेणी $32,36,40,\ldots$ के पहले (22) पदों का योग कितना है?

What is the sum of the first (22) terms of the AP $32,36,40,\ldots$?

Explanation opens after your attempt

Correct Answer

C. (1628)

Step 1

Concept

The twenty-second term is $32+21\cdot4=116$. (S_{22}=\frac{22}{2}(32+116)=1628).

Step 2

Why this answer is correct

The correct answer is C. (1628). The twenty-second term is $32+21\cdot4=116$. (S_{22}=\frac{22}{2}(32+116)=1628).

Step 3

Exam Tip

बाईसवां पद $32+21\cdot4=116$ है। (S_{22}=\frac{22}{2}(32+116)=1628)।

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Class 10 Mathematics Easy Quiz

समान्तर श्रेणी \(2,5,8,\ldots\) के पहले (10) पदों का योग क्या है?

Concept

Why this answer is correct

Exam Tip

समान्तर श्रेणी \(4,8,12,\ldots\) के पहले (15) पदों का योग ज्ञात कीजिए।

Concept

Why this answer is correct

Exam Tip

यदि (a=6), (d=2), (n=20) है तो \(S_n\) क्या होगा?

Concept

Why this answer is correct

Exam Tip

समान्तर श्रेणी \(1,3,5,\ldots\) के पहले (25) पदों का योग क्या है?

Concept

Why this answer is correct

Exam Tip

समान्तर श्रेणी \(10,20,30,\ldots\) के पहले (12) पदों का योग कितना है?

Concept

Why this answer is correct

Exam Tip

समान्तर श्रेणी \(7,14,21,\ldots\) के पहले (10) पदों का योग क्या होगा?

Concept

Why this answer is correct

Exam Tip

यदि किसी AP का पहला पद (5), अंतिम पद (45) और पदों की संख्या (9) है तो योग क्या है?

Concept

Why this answer is correct

Exam Tip

समान्तर श्रेणी \(3,6,9,\ldots\) के पहले (30) पदों का योग ज्ञात कीजिए।

Concept

Why this answer is correct

Exam Tip

समान्तर श्रेणी \(20,18,16,\ldots\) के पहले (8) पदों का योग क्या है?

Concept

Why this answer is correct

Exam Tip

यदि AP \(9,13,17,\ldots\) है तो पहले (11) पदों का योग क्या है?

Concept

Why this answer is correct

Exam Tip

समान्तर श्रेणी \(12,17,22,\ldots\) के पहले (14) पदों का योग कितना है?

Concept

Why this answer is correct

Exam Tip

समान्तर श्रेणी \(5,10,15,\ldots\) के पहले (18) पदों का योग क्या होगा?

Concept

Why this answer is correct

Exam Tip

यदि (a=8), (d=3), (n=16) है तो \(S_{16}\) कितना होगा?

Concept

Why this answer is correct

Exam Tip

समान्तर श्रेणी \(6,11,16,\ldots\) के पहले (9) पदों का योग क्या है?

Concept

Why this answer is correct

Exam Tip

पहले (20) प्राकृतिक संख्याओं का योग क्या है?

Concept

Why this answer is correct

Exam Tip

पहले (16) सम प्राकृतिक संख्याओं का योग कितना है?

Concept

Why this answer is correct

Exam Tip

समान्तर श्रेणी \(15,25,35,\ldots\) के पहले (13) पदों का योग क्या है?

Concept

Why this answer is correct

Exam Tip

यदि पहले (n) पदों का योग (S_n=\frac{n}{2}(3n+1)) है तो \(S_{10}\) क्या होगा?

Concept

Why this answer is correct

Exam Tip

समान्तर श्रेणी \(30,27,24,\ldots\) के पहले (10) पदों का योग ज्ञात कीजिए।

Concept

Why this answer is correct

Exam Tip

एक AP का (a=2), (l=38) और (n=10) है। \(S_n\) क्या होगा?

Concept

Why this answer is correct