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Which option correctly gives the HCF of (2^3\times3^2\times7) and (2^5\times3\times7^2)?
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Answer and explanation
Correct answer: (2^3\times3\times7)
Step 1: HCF takes the smaller power of each common prime. Step 2: The smaller powers of (2), (3), and (7) are (3), (1), and (1), so HCF (=2^3\times3\times7). Step 3: Match each smaller power with the correct base.
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What is the correct answer to this question?
(2^3\times3\times7)
Why is this the correct answer?
Step 1: HCF takes the smaller power of each common prime. Step 2: The smaller powers of (2), (3), and (7) are (3), (1), and (1), so HCF (=2^3\times3\times7). Step 3: Match each smaller power with the correct base.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.
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