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Which algebraic law is represented by \(p(q+r)=pq+pr\)?

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Answer and explanation

Correct answer: Distributive law

In the left-hand side, \(p\) is multiplied separately by both terms inside the parentheses, \(q\) and \(r\): \(p(q+r)=pq+pr\). Therefore, it represents the distributive law. The associative law changes grouping, whereas this expression distributes multiplication over addition. Exam tip: whenever you see \(a(b+c)=ab+ac\) or \(a(b-c)=ab-ac\), identify the distributive law.

Related tags

PolynomialsReal Number LawsDistributive LawAlgebraic Identities

Frequently asked questions

What is the correct answer to this question?

Distributive law

Why is this the correct answer?

In the left-hand side, \(p\) is multiplied separately by both terms inside the parentheses, \(q\) and \(r\): \(p(q+r)=pq+pr\). Therefore, it represents the distributive law. The associative law changes grouping, whereas this expression distributes multiplication over addition. Exam tip: whenever you see \(a(b+c)=ab+ac\) or \(a(b-c)=ab-ac\), identify the distributive law.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Operations on real numbers and the laws of exponents.

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