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Which fraction will have a terminating decimal expansion even though the given denominator shows a factor (13)?

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Answer and explanation

Correct answer: (\frac{91}{2^2\cdot 5\cdot 13})

Step 1: (91=7\cdot 13), so the factor (13) in the denominator cancels. Step 2: The reduced denominator is (2^2\cdot 5), containing only (2) and (5). Hence the decimal terminates. Step 3: An extra prime factor may cancel with the numerator.

Related tags

CancellationTerminating-DecimalTricky-McqReal-Numbers

Frequently asked questions

What is the correct answer to this question?

(\frac{91}{2^2\cdot 5\cdot 13})

Why is this the correct answer?

Step 1: (91=7\cdot 13), so the factor (13) in the denominator cancels. Step 2: The reduced denominator is (2^2\cdot 5), containing only (2) and (5). Hence the decimal terminates. Step 3: An extra prime factor may cancel with the numerator.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Decimal expansion of rational numbers.

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