कौन सा समीकरण वास्तविक, अपरिमेय और भिन्न मूल रखता है?
Which equation has real, irrational and distinct roots?
Explanation opens after your attempt
B. \(x^2-2x-2=0\)
Concept
In the second equation (D=(-2)2-4(1)(-2)=12). (12) is positive but not a perfect square.
Why this answer is correct
The correct answer is B. \(x^2-2x-2=0\). In the second equation (D=(-2)2-4(1)(-2)=12). (12) is positive but not a perfect square.
Exam Tip
दूसरे समीकरण में (D=(-2)2-4(1)(-2)=12) है। (12) धनात्मक है पर पूर्ण वर्ग नहीं है।
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