कौन सा समीकरण वास्तविक, अपरिमेय और भिन्न मूल रखता है?

Which equation has real, irrational and distinct roots?

Explanation opens after your attempt
Correct Answer

B. \(x^2-2x-2=0\)

Step 1

Concept

In the second equation (D=(-2)2-4(1)(-2)=12). (12) is positive but not a perfect square.

Step 2

Why this answer is correct

The correct answer is B. \(x^2-2x-2=0\). In the second equation (D=(-2)2-4(1)(-2)=12). (12) is positive but not a perfect square.

Step 3

Exam Tip

दूसरे समीकरण में (D=(-2)2-4(1)(-2)=12) है। (12) धनात्मक है पर पूर्ण वर्ग नहीं है।

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कौन सा समीकरण वास्तविक, अपरिमेय और भिन्न मूल रखता है? / Which equation has real, irrational and distinct roots?

Correct Answer: B. \(x^2-2x-2=0\). Explanation: दूसरे समीकरण में (D=(-2)2-4(1)(-2)=12) है। (12) धनात्मक है पर पूर्ण वर्ग नहीं है। / In the second equation (D=(-2)2-4(1)(-2)=12). (12) is positive but not a perfect square.

Which concept should I revise for this Mathematics MCQ?

In the second equation (D=(-2)2-4(1)(-2)=12). (12) is positive but not a perfect square.

What exam hint can help solve this Mathematics question?

दूसरे समीकरण में (D=(-2)2-4(1)(-2)=12) है। (12) धनात्मक है पर पूर्ण वर्ग नहीं है।