What type of decimal expansion will (\frac{200}{2^3\cdot 5^3\cdot 7}) have?
Answer and explanation
Correct answer: Non-terminating recurring
A rational number has a terminating decimal only when, after cancellation, its denominator has no prime factors other than 2 and 5. If another prime factor remains, the division cannot end; because remainders repeat, the decimal becomes non-terminating recurring. This rule helps classify the decimal without carrying out a long division.
Here, the numerator is 200 = \(2^3\times5^2\). Cancelling common factors with \(2^3\times5^3\times7\) leaves the denominator \(5\times7\), since one factor 5 and the factor 7 remain. The factor 7 is not allowed in a terminating denominator, so the decimal is non-terminating recurring. Therefore option B follows.
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What is the correct answer to this question?
Non-terminating recurring
Why is this the correct answer?
A rational number has a terminating decimal only when, after cancellation, its denominator has no prime factors other than 2 and 5. If another prime factor remains, the division cannot end; because remainders repeat, the decimal becomes non-terminating recurring. This rule helps classify the decimal without carrying out a long division.
Here, the numerator is 200 = \(2^3\times5^2\). Cancelling common factors with \(2^3\times5^3\times7\) leaves the denominator \(5\times7\), since one factor 5 and the factor 7 remain. The factor 7 is not allowed in a terminating denominator, so the decimal is non-terminating recurring. Therefore option B follows.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Decimal expansion of rational numbers.
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