रेखा (5x+2y=20) का (x)-अवरोध कौन-सा है?
What is the (x)-intercept of the line (5x+2y=20)?
Explanation opens after your attempt
A. बिंदु (\left\(4,0\right\))Point (\left\(4,0\right\))
Concept
Putting (y=0) gives (5x=20), so (x=4). In an (x)-intercept, the (y)-coordinate is (0).
Why this answer is correct
The correct answer is A. बिंदु (\left\(4,0\right\)) / Point (\left\(4,0\right\)). Putting (y=0) gives (5x=20), so (x=4). In an (x)-intercept, the (y)-coordinate is (0).
Exam Tip
(y=0) रखने पर (5x=20), इसलिए (x=4)। (x)-अवरोध में (y)-निर्देशांक (0) होता है।
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