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What is the value of \(\left(\frac{4}{3}\right)^{-2}\cdot\left(\frac{16}{9}\right)\)?
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Answer and explanation
Correct answer: (1)
\(\left(\frac{4}{3}\right)^{-2}=\left(\frac{3}{4}\right)^2=\frac{9}{16}\). Hence \(\frac{9}{16}\cdot\frac{16}{9}=1\).
Frequently asked questions
What is the correct answer to this question?
(1)
Why is this the correct answer?
\(\left(\frac{4}{3}\right)^{-2}=\left(\frac{3}{4}\right)^2=\frac{9}{16}\). Hence \(\frac{9}{16}\cdot\frac{16}{9}=1\).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Operations on real numbers and the laws of exponents.
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