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What is the value of \(\left(\frac{2}{3}\right)^{-3}\cdot\left(\frac{9}{4}\right)^{-1}\)?
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Answer and explanation
Correct answer: (6)
\(\left(\frac{2}{3}\right)^{-3}=\left(\frac{3}{2}\right)^{3}=\frac{27}{8}\) and \(\left(\frac{9}{4}\right)^{-1}=\frac{4}{9}\), so the product is (6). In exams, invert the fraction for negative powers.
Frequently asked questions
What is the correct answer to this question?
(6)
Why is this the correct answer?
\(\left(\frac{2}{3}\right)^{-3}=\left(\frac{3}{2}\right)^{3}=\frac{27}{8}\) and \(\left(\frac{9}{4}\right)^{-1}=\frac{4}{9}\), so the product is (6). In exams, invert the fraction for negative powers.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Operations on real numbers and the laws of exponents.
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