0 reads0 ratings0 helpful
What is the value of \(\left(32^{\frac{2}{5}}\right)\cdot\left(4^{-\frac{3}{2}}\right)\)?
Advertisement
Answer and explanation
Correct answer: \(\frac{1}{2}\)
Here \(32^{\frac{2}{5}}=(2^{5})^{\frac{2}{5}}=2^{2}=4\), and \(4^{-\frac{3}{2}}=(2^{2})^{-\frac{3}{2}}=2^{-3}=\frac{1}{8}\). The product is \(\frac{1}{2}\).
Frequently asked questions
What is the correct answer to this question?
\(\frac{1}{2}\)
Why is this the correct answer?
Here \(32^{\frac{2}{5}}=(2^{5})^{\frac{2}{5}}=2^{2}=4\), and \(4^{-\frac{3}{2}}=(2^{2})^{-\frac{3}{2}}=2^{-3}=\frac{1}{8}\). The product is \(\frac{1}{2}\).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Operations on real numbers and the laws of exponents.
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
Advertisement